MAE140 Linear Circuits Fall 2006 Quiz. Thursday October 26 in class, 60 minutes
Instructions
This quiz is open book. You may use whatever written materials you choose including your class notes and the textbook. You may use whatever calculator you d
MAE140 Linear Circuits Fall 2006 Quiz. Thursday October 19 in class, 80 minutes
Instructions
This quiz is open book. You may use whatever written materials you choose including your class notes and the textbook. You may use whatever calculator you d
Solutions to MAE140 Linear Circuits Quiz # 2 -November 12, 2002 Question 1
1. Obvious labeling of nodal voltages. 2. Node A: G1 (vin - v A ) + G1 (v B - v A ) = 0, iN = 0 v B = 2v A - vin iN = 0, iout = GL vC Node C: iout + G3 (vC - v E ) = 0 Node D:
MAE140 Linear Circuits Quiz # 1 - October 17, 2002 Solutions
Question 1 - Circuit Concepts
(a) Begin by computing the current and voltage of the load resistors. R1 = 40W : P = 40W , i = 1A, v = 40V R1 = 10W : P = 40W , i = 2A, v = 20V Now use the cir
MAE140 Linear Circuits Quiz # 1 - January 29, 2002
Instructions
This quiz is open book. You may use whatever written materials you choose including your class notes and the textbook. You may use whatever calculator you desire, provided it has no mess
MAE140 Linear Circuits Quiz # 1 - January 29, 2002
Answers Question 1
(a) 1. Power is proportional to v2/R or R v2/P. Thus, if a 100W bulb has resistance of 60 , then a 50W bulb should have a resistance of 120. 2. If we double the voltage from 110V to 220
MAE140 Linear Circuits Summer 1 2006 Quiz Solutions. Wednesday July 19
Question 1: Nodal Analysis
Part (i): (a) Set node D to be the grounded node and refer all other nodal voltages to that. (b) By inspection, the nodal voltage vA relative to node D
MAE140 Linear Circuits Summer 1 2005 Quiz. Wednesday July 19 in class, 80 minutes
Instructions
This quiz is open book. You may use whatever written materials you choose including your class notes and the textbook. You may use whatever calculator you
MAE140 Linear Circuits Summer 1 2005 Quiz Solutions. Wednesday June 29
Question 1: Mesh Analysis
Part (i): Note that, because of the current source i isolated in mesh one, we have that current i1 = i. Thus, considering the mesh equation for the seco