1706
IEEE JOURNAL OF QUANTUM ELECTRONICS, VOL. 33, NO. 10, OCTOBER 1997
Laser Ablation and Micromachining
with Ultrashort Laser Pulses
X. Liu, D. Du, and G. Mourou
Abstract The mechanisms of ultrashort-pulse laser ablation
of materials are discussed, the
Indian Institute of Technology Kharagpur
End Autumn Semester Examination 2010-2011
Subject Code: m Subject: Computer Integrated Manufacturing Date: ignyzom
Departments: ME+MF 14‘“ Year+DD1 Number of students: AL Duration: 3 H5
Section A: Answer all questi
Indian :Institute of Technology Kharagpur
End Autumn Semester Examination
Course Code: MF40603
Course Name: Computer Integrated Manufacturing
Students= 55
Departments: ME, MF, IEM.
Time: 3hrs.
1
Date: 19 h Nov 2012
Full Marks 100
Instructions: Answer all
Chem Soc Rev
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Part A
Fx Rx
Rx F3 cos 45 F2 4 / 5 F1
200 1 / 2 260 4 / 5 310
376.57 lb
Fy Ry
Ry F3 sin 45 F2 3 / 5
200 1 / 2 260 3 / 5
297.42 lb
R
Rx
2
Ry
376.57
2
2
297.42
2
479.85 lb
Part B
Ry
Rx
tan
297.42
376.57
0.78
tan 1 0.78
37.95
Part C
The bending moment diagram and the reactions at the supports are
shown in the figure below.
The maximum bending moment is 3000 lb-ft.
The equivalent section for one of the three materials is transformed
as,
The position of neutral plane is determined as,
Consider the
T s
diagram of an ideal regenerative Rankine cycle.
The turbine inlet conditions are 10 MPa and
.
480 C
From the table A-5, fluid temperature is greater than the saturation
temperature, corresponding to 10 MPa
.
311C
Therefore, the steam is
Calculate the mean film temperature,
20 100
Tf
2
60F
=288.706 K
The properties of air at
70F
are,
1
288.706
3.463 103
k 0.0254 W / m K
Pr 0.713
v 14.7 106 m 2 /s
Calculate the value of Gr,
g Tw T L3
Gr
v2
9.8 3.463 103 100 20 2 0.3048
2
14.7 106
7.
The braking force on car A is,
FbA k mA g
0.6 25000 9.8
147000 N
Free body diagram of car A is,
F
x
A
mA a A
Fc Fb mA a A
Fc 147000 25000 a A 1
Free body diagram of car B is,
F
x B
mB aB
Fb Fc mB aB
147000 Fc 20000 a A 2
Adding (1) and (2), we
4
Application Layer Protocols
4.1
Device Management Protocols
Contents
This part treats device remote access in order of increasing complexity
4.1.1 current loop 4.20 mA
4.1.2 HART
4.1.3 SNMP: Simple Network Management Protocol
4.1.4 MMS: Manufacturing Me
2
Industrial
Communication
Technology and
Systems
2-1
2005 by CRC Press
I
Field Area and
Control Networks
7 Fieldbus Systems: History and Evolution .7-1
Thilo Sauter
8 The WorldFIP Fieldbus .8-1
Jean-Pierre Thomesse
9 FOUNDATION Fieldbus: History and Fea
4
Application Layer Protocols
4.2
Open Process Control (OPC)
OPC: Open Process Control
Source: http:/home.hit.no/~hansha/documents/lab/Lab%20Work/opc.htm
OPC: Open Process Control
Manufacturer-independent application programming interface (API) for automa
Consider the computational domain shown in Figure 5.1.Expanding W and S about
P using a Taylor series, we get
x 2 2
2! x2
x 3 3
3! x3
f d
x
f d
x
P
(5.45)
oo
CHo
W
y 2 2
y 3 3
y
2! y2
3! y3
All derivatives in the above equations are evaluated at P. R
General Oral Presentation and E - Poster Guidelines
All Oral and E-poster presentations will be played/viewed on Linux based computers. Your presentation
must be prepared in PowerPoint and saved as a .pptx, .pdf, .odp file. Set the slide size of the page
Advances in Computational Mathematics 19: 333, 2003.
2003 Kluwer Academic Publishers. Printed in the Netherlands.
Development and analysis of higher order nite volume
methods over rectangles for elliptic equations
Zhiqiang Cai , Jim Douglas, Jr., and Moo
Automation of Manufacturing:
CNCs, Industrial Motion Control,
Motor Control and PLCs
CI(D)M Class
2014
Numerical Control
Numerical control is a method of
automatically operating a manufacturing
machine based on a code of letters, numbers,
and special cha
PLC Programming
Manufacturing Automation
CIM Class
Developing programs for PLCs
Multiple use in factory automation
Links up several machines, robots and
transportation systems
Inputs and outputs need to be redefined
Sequencing Logic needs to be
progra
Industrial Automation Networks
CIM Class 2015
Industrial Automation 2015
Industrial Automation and MES - 1
Industrial Automation
7
Application
6
Presentation
5
Session
4
Transport
3
Network
2
Link
1
Physical
Industrial Communication Systems
Open System In
Manufacturing Execution
Systems
CIM 2015
Project
Definition
Operations,
Asset Mgmt
ERP
Design,
Procurement
MES
Process Control
Commissioning,
Debugging
Field
Fabrication
Installation,
Checkout
Manufacturing Execution System = MES
Case : Manufacturing mode
PLC in Industrial Control and
Automation
CI(D) Lecture Class
2014
PLC
Programmable
Logic
Controller
The first PLC was developed by a group of
engineers at General Motors in 1968, when
the company were looking for an alternative
to replace complex relay co
Engineering strains are given by,
L
E
L
L
1.5
5
L 7.5
For the specimen that is in tension, final length is given by,
L 7.5
L f Li 7.5
L f 7.5 5
12.5 cm
For the specimen in compression, final length is,
L f Li 7.5
L f 7.5 5
2.5
Final length is negative
The velocity component in x-direction is,
vx 15 m/s
The velocity component in y-direction is obtained by using chain
rule,
dy
vy
dt
d 0.07 x 2
dt
dx
0.14 x
dt
0.14 x v x
The x-component of acceleration is,
d vx
ax
dt
0
The y-component of acceler
Here, point A is fixed.
Hence, the velocity of any point with respect to A gives the
absolute velocity.
Calculate the magnitude of velocity of point B with respect to A.
VB 1 AB
90.161 0.2
18.03 m/s
Choose a suitable scale to draw velocity vector diagra
After saturation, the total pressure inside the chamber is equal to
the sum of partial pressure of nitrogen and partial pressure of water
vapour at
.
27C
At saturated state, the partial pressure of water is equal to the
vapour pressure of water at
.
27C
p
The magnitude of the distributed load, P is
F P L b
275 psi 8 3
6600 lbf
The cross sectional area of the bolt is,
2
Ab db
4
2
0.625
4
0.306796 in 2
Shear stress in each bolt is,
F
Ab
6600
0.306796
21512.66 psi
Average shear stress is ,
avg
2
215
Apply conservation of mass principle to the chamber.
& & &
m1 m2 m3
&
1 AV1 m2 3 A3V3
1
The density of air at
15 C
is
Volume flow rate at inlet 1 is
1.2 0.01 0.02 1.2
V3 0.84 m/s
1.2 kg/m
AV1
1
3
.
=0.01
0.22 V3
4
m 3 /s
Element 1:
The angle between local and global x and
C cos90 0
S sin 90 1
Calculate the following for element 1,
12 I 12 2 104
L12
42
x
axes is 900.
1.5 104 m 2
6 I 6 2 104
L1
4
3 104 m3
E 70 109
L1
4
175 108 N/m 3
Obtain the element global stiffness ma
The position vector of point A is,
rA 0.5sin 30i 0.5cos30 j
0.25 i+0.43 j
The position vector of point B is,
rB 0.5cos30 j 0.5sin 30k
0.43 j+0.25 k
The position vector from A to B is,
rAB rB rA
0.43 j 0.25 k 0.25 i 0.43 j
0.25 i 0.25 k
Force F exp