Testname: MAT2058 Week 4 Practice Quiz
Answer Key
1. A; The (total) width of the confidence interval is 0.52 - 0.432 = 0.088; E = half this width, =
0.044.
2. D; First need to solve for p-hat = 69/130 = 0.5308; then find E = 1.645* pq /n =
1.645*0.0438 =
In the test statistic formula can you identify what each variable stands for:
zan-Pi'sortPu-pn
what does
Fm and P stand for?
H, Im Allan. Welcome to Smarthinking
ley again Allan.
FM 2 sample proportion
P : population proportion
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MAT2058 Week 3 Practice Quiz
Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and
standard deviation 1.
1)
Shaded area is 0.4013.
1)
_
A)
-0.57
B)
-0.25
C)
0.57
D)
0.25
Find the area of the shaded region. The grap
MAT2058 Week 4 Practice Quiz
MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers
the question.
Express the confidence interval using the indicated format. Please show all work for all
problems!
1)
Express the confidenc
Example Using the Continuity Correction
See p. 348 #6.94: 30% of students entering a certain university drop out during or at the end of their
first year. What is the probability that more than 600 of this years entering class of 1800 will drop out
during
724
Appendix A
Tables
NEGATIVE 2 Scores
z 0
Table A-2 Standard Normal (2) Distribution: Cumulative Area from the LEFI'
z .02 .03 .04 .05 .03 .07 .03 .09
3.50 and .0001 0196
lower I
3.4 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0002
3.3 .0