Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Solution to Homework #9
1. (a) When the swings are small, we can ignore the current drawn by RL , then IC I1
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Solution to Homework #8
1. The open-loop gain and I/O impedances are
Av,open = gm1 (R1 + R2 ), Rin,open =
r1
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Solution to Homework #7
1. First, we determine the open-loop gain and I/O impedances of the feedforward netwo
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Solution to Homework #6
1. (a) The open-loop gain is A1 and the feedback factor is K R1R2 2 . Therefore, the
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Solution to Homework #5
1. First, draw the small-signal equivalent circuit (by yourself). Then
IX =
1
VX
sC1
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Solution to Homework #4
1. (a) The transistor capacitances are shown in Figure 1(a). CCS1 , C2 , and CL are i
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Solution to Homework #3
1. (a) The DC voltage gain is AV = gm1 . The pole and -3-dB bandwidth of the circuit
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Solution to Homework #2
1. Based on the concept of half-circuit, the output impedance Rout is
Rout = [1 + gm3
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Solution to Homework #1
1. The voltage at node P is
VP = VCC (I1 + I2 )R1 = VCC 2I0 R1
The peak-to-peak swing
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Homework #9
Unless otherwise stated, assume VCC = 5 V, VEE = 5 V, VA = , and
1 in the following problems.
1.
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Homework #8
1. Consider the feedback amplier circuit shown in Figure 1. Assume R1 + R2 is not very large, 1
a
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Homework #7
1. Consider the feedback circuit shown in Figure 1, where C1 and C2 are very small and other capa
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Homework #6
1. Calculate the closed-loop gain of the circuits shown in Figure 1. Assume the op amp exhibits a
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Homework #5
1. The circuit shown in Figure 1 is called an active inductor. Neglect other capacitances and ass
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Homework #4
1. For the bipolar circuits shown in Figure 1, identify all of the transistor capacitances and de
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Homework #3
1. Construct the Bode plot of |Vout /Vin | and determine the -3-dB bandwidth for the circuits sho
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Homework #2
1. Calculate the voltage gain of the degenerated pair depicted in Figure 1. VA < . (Hint: Av = Gm
Department of Electrical Engineering, Tamkang University
Microelectronics (III), Fall 2009
Homework #1
1. In the circuit of Figure 1, I1 = I0 cos wt + I0 and I2 = I0 cos wt + I0 . Plot the waveforms a
Department of Electrical Engineering, Tamkang University
Microelectronics, Summer 2008
Solution to Homework #10
1. Based on the concept of half-circuit, the output impedance Rout is
Rout = [1 + gm3 (r
Department of Electrical Engineering, Tamkang University
Microelectronics, Summer 2008
Solution to Homework #9
1. The voltage at node P is
VP = VCC (I1 + I2 )R1 = VCC 2I0 R1
The peak-to-peak swing of
Department of Electrical Engineering, Tamkang University
Microelectronics, Summer 2008
Solution to Homework #8
1. Let IB be the base current goes through the resistor RP , we have
I1
IREF I1
IB = IB
Department of Electrical Engineering, Tamkang University
Microelectronics, Summer 2008
Solution to Homework #7
1. (a) Since Rp is in parallel connection with r1 , we have
Rout = [1 + gm1 (r1 |RP |rO2
Department of Electrical Engineering, Tamkang University
Microelectronics, Summer 2008
Solution to Homework #6
1. (a) When Vin > VD,on /A0 0, D1 is ON and
A0 [Vin (VY VD,on )] = VY VY =
A0
A0
Vin +
VD
Department of Electrical Engineering, Tamkang University
Microelectronics, Summer 2008
Solution to Homework #5
1. To nd the closed-loop gain, we consider the equivalent circuit shown in Figure 1(a). B
Department of Electrical Engineering, Tamkang University
Microelectronics, Summer 2008
Solution to Homework #4
1. The input impedance Rin is given by
Rin =
1
1
1
.
50 =
gm1 =
gm1
gm1
50
The output i
Department of Electrical Engineering, Tamkang University
Microelectronics, Summer 2008
Solution to Homework #3
1. Since ID1 is 0.5 mA, assume M1 operates in the saturation region, we have
ID1 =
1
W
1
Department of Electrical Engineering, Tamkang University
Microelectronics, Summer 2008
Solution to Homework #2
1. (a) VGS = 1 V and VDS = VDD ID RD . We assume M1 operates in the saturation region, th
Department of Electrical Engineering, Tamkang University
Microelectronics, Summer 2008
Solution to Homework #1
1. This combination can be treated as a series connection of two resistors. The width and
Department of Electrical Engineering, Tamkang University
Microelectronics, Summer 2008
Homework #10
1. Calculate the voltage gain of the degenerated pair depicted in Figure 1. VA < . (Hint: Av = Gm Ro
Department of Electrical Engineering, Tamkang University
Microelectronics, Summer 2008
Homework #9
1. In the circuit of Figure 1, I1 = I0 cos wt + I0 and I2 = I0 cos wt + I0 . Plot the waveforms at X,