Binding pulls equilibrium one way
Low afnity is more thermodynamically stable in the absence of the ligand
Sequential is more physically realistic. The problem is math is impossible for n greater than 2.
Independent, each ligand doesn't know if the other
We normally write rate constants as positive so to make it decreasing we have to add the negative sign.
A and b have to collide in the correct eometrywith the corrects mount of energy to react.
Hydroxide is an inhibition in the reaction
What's the proper S0 to use.
Linear regressions if add all the misses up, they add to zero. The average error
As you produce product, you slow the reaction down
An enzyme has some afnity for its product so its a self-i
P* = vapor pressure of ideal substance
1 gas phase must behave as ideal gases
Molecules a and b interact
identically to the way a and a
interacts and B and B
Things break down past the freezing point since they are so different
The liquid should be r
Never assume that ionic solutions behave the same way that neural solutions do.
Extremely strong infractions between the solvent, water,
Gas phase takes a ton of energy to get to than the aqueous solution.
Step 3 must be the difference between 1 and 2
Ligands bound per n?
At low k times l, then the denominator is close to one and nu is k times 1.You get a linear
If plot NU versus l, the half saturation point of l is where k times l equals one and
you can read k off the graph
Nice linear rise fr
A is the rate at innity temperature, enough energy for something to always occur
This rate is talking about something occurring in femtosecond, the speed of
The vibration of a molecule. Extremely fast rate
Once it achieves the activation barrier, it goe
First step is very slow relative to the second steps can never build up a high concentration of b because the intermediate is consumed fairly rapidly
once it is formed. [b] ~ const
Formation of a is only related to .
Relates to the reactive rate is forw