d
q i y i u s i i q q h q u y q u s q m
r%TfTv%TTTrrTfxTv5hpn
q i y i q h q l l y u s y d i q s s d h s w y h q d i q u s q m
T0TxhsrTTf4'%vtfahrpp'p%vpa%GxTpTpn
q i y i q s h s i q u s q m
rTTfTxpkvExTv50
q i y i u s i i q u s q
r%TfTv%TTpxTpQn
irqr%
Solutions Homework 3
1a. With 25% excess bandwidth the useable (Nyquist) bandwidth is 80 kHz, since (100
80)/80 = 25%, and the symbol rate is 80,000 symbols/sec. A modulation format with 8
points in the constellation, such as 8 PSK, gives the data rate 2
-1-
SOLUTIONS, WIRELESS HW #2
1a. The path loss exponent is 37/10 = 3.7. Increasing the distance from 1 km to 10 km
means the average received power decreases by 37 dB, which is a factor of 0.0002. Hence
the received power is 1 mW x 0.0002 = 0.0002 mW = 0
-1-
SOLUTIONS, WIRELESS HW #1
1. The standards are arranged from lowest to highest data rate. (Some of the rates come
from various Wikipedia sites and differ from what are on the slides for Week 1.)
AMPS; 1G; did not support data services
GSM; 2G; the cor