Evaluation:
The expected value of Kc = 4. The percentage of error
can be calculated as follows:
Percentage of error = (4 - 3.9825) I
4 * 100% = 0.4375%
Although I consider my technique to be correct a
Mixture2:
e
Mass of CH3COOH = 1.05 * 75 = 78.75 g
Molecular mass of
CH3COOH = 12 + 3 +12 + 32
+ 1 = 60 g/mol Number of
moles of CH3COOH = 78.75 /
60 = 1.3125 mole
Mass of C2H50H = 0.79 * 75 = 59.25 g
Predictions:
1. CH3COOC2H5, C2H5OH and CH3COOH are going to
be the major products in experiments 2, 3 and 4
respectively because their initial amounts are all zero
whereas H2O, CH3COOH, and C2H5OH are
Mixture4:
I
e
Mass of CH3COOH = 0 g
Number of moles of CH3COOH = 0 mole
Mass of C2H50H = 0.79 * 75 = 59.25 g
Molecular mass of C2H50H =
24 + 5 + 16 + 1 = 46 g/mol
Number of moles of C2H50H
e
= 59.2
Apparatus:
Meter Stick
Stopwatch
Protractor
String (non extensible)
Pendulum bob (minimal air resistance; metal)
Lab stand
Cartesian graph paper
Method:I) Set up the simple pendulum. Check to m
TheDeterminationofanEquilibriumConstant
Introduction:
PART:Theory
Many chemical reactions are irreversible reactions, for example, if magnesium
is burnt in air a brilliantwhiteflameisobservedasthewhit
Method
Method to prepare solutions
1. Concentration required (CuS04): 0.99M AMU
of CuS04: 159.61
So, 1.00M of CuS04 has 159.61g of CuS04
Hence 0.99M has: 159.61 x 0.99
= 158.01g 0.01g
Mix 158.01g 0.01
TheSimplePendulumLab
ResearchQuestion:
To investigate how the length factor of a pendulum string will affect the time
period of a pendulum and to attempt and determine a mathematical relationship betw
Also in the table above I have found the values for T squared, or the period
squared. This was done because the theoretical formula shows that there should be a
linear relationship between the length
Concentration and equilibrium
The equilibrium positions for reactions in the liquid phase are
affected by changes in the concentration of products and
reactants.
[Co (H20)6]2+ + 4Cl-
[CoCl4]2- + 6H20