CHAPTER TWO
2.1 (a)
= 18144 10 9 ms . 1 wk 1 d 1 h 1 s 38.1 ft / s 0.0006214 mi 3600 s (b) = 25.98 mi / h 26.0 mi / h 3.2808 ft 1 h 3 wk 7d 24 h 3600 s 1000 ms
(c)
554 m 4 1d 1h d kg 24 h 60 min
1 kg 108 cm 4 = 3.85 10 4 cm 4 / min g 1000 g 1 m 4
2.2 (a)
ChBE 221 Homework #2
Problem #1
A basis of 1 kg is specified.
Problem #2
A basis of 1 kg of solution will be used for this solution
For the rate at the exit:
Problem #3
Pressure gauge must be giving a gauge pressure for this problem.
Convert the barometri
1. To determine whether mass balance holds under given conditions, compare mole ratios of
C/H, O/C, and O/H ENTERING AND EXITING
Basis: 100 lbmoles Product
As all of the C and H come from the inlet methane.
1
4
= at the input methane, so it should
equal a
CHBE 221 Homework 3 Key. Homework due Sept 26
1) Assume Steady State and No Chemical Reactions
Degrees of Freedom= nvariables - nequations
12 variables listed (F, P, D, , , , , , , , , )
We know 5 of them (given in the problem)
There are 3 chemical specie
Homework Solution 1
ChBE 221
Problem 1
Remember that pound-mole is defined as the number of entities in 12 lb-m of carbon 12. One lb-mol is
equal to 453.59 mol, (same as 453.59 grams per pound). Here the molecular weight of ammonia is 17 lb/lbmol (Same as
Homework #5 ChBE 221 Fall 2014
Question 1
Step 1, 2, 3, 4
Step 5: Basis: 100 mol F
Step 6: Unknowns: P, x,y,z
Step 7; Mass balance on C, H, O, N from which can solve the unknowns
Step 8 and 9: Air is based on complete combustion
So, CO + O2 CO2
and CH4 +2