Homework 6 4.1 (c) and (d) The force of electrical origin is just the partial of coenergy with respect to x. There is only one current, so we need to only integrate w.r.t. i.
Taking the partial with respect to x:
Since this is a magnetically linear system
ECE 430 homework assignment #1 (In class quiz Thursday/Friday, Sep 4/5)
Text problem 2.1 (Partial answer: 0.707 leading) Text problem 2.2 (Partial answers: -250, -500, 500, 0, 150, 1900, -150) Text problem 2.8 Text problem 2.9 Text problem 2.10 (Partial a
ECE 430 homework assignment #3 (In class quiz Thurs/Fri, Sep 18/19)
Text problem 3.1 (and also find the magnetic flux density in the iron) (partial answer: L = 6.1 mH) Text problem 3.2b (part b only) (partial answer: L11=3.125mH, L22=0.78125mH) Text probl
Text 3.2 a) The dots go on the upper left and lower right, respectively. b) See previous assignment, text 3.2b. c) lambda_1 = L11*i1 - L12*i2 lambda_2 =-L21*i1 + L22*i2 where L11 = 3.125 mH, L12=L21= 0.938 mH, L22 = 0.781 mH, Text 3.10 a)
If the transform
Assignment 7 FS 2007 ECE 430 Text 4.8 a) First find the coenergy. It is magnetically linear, so we can simply sum up the 1/2*Lpq*ip*iq terms:
To get the torque, just take the derivative with respect to theta: b) We are not given the angle, so the torque w
ECE 430 homework assignment #10 (In class quiz Thu/Fri, Dec 4/5)
Text problem 7.3 Text problem 7.4 Text problem 7.11 Text problem 7.14 Special problem #1 (see solution Spring 2005 final) A 460 Volt (line to line), 60 Hz, 3-phase, Y-connected, 4 pole Induc