Quiz 2
May 5, 2008
1. (a) What is Brewsters angle? (b) Calculate the Brewster angle for a plate of crown
n cos 1 n1 cos 2
glass (n=1.52) in air. (Hint: use r/ = 2
and Snells law).
n2 cos 1 + n1 cos 2
2. (a) What is evanescent wave? (2) Prove that evanesce
ELEC308 (Spring 2008)
Quiz 2
TA solution
Problem 1
(a). Brewsters angle is a particular angle of incidence at which the incoming unpolarized
wave made up of two incoherent orthogonal states, only the component polarized normal
to the incident plane and th
Quiz 1 (Total: 5 points + 1 points bonus)
March 7, 2008
1. (1.5 pts.) What is wave-particle duality of light? Describe two experiments to show
that light has wave-particle duality.
2. (1 pts.) A Ray of yellow light from sodium discharge lam falls on the s
Quiz 1
TA Solution
Problem 1
Wave-particle duality is a property of light. All phenomena of light can be explained
using either the wave or particle picture. Usually, one or the other is most convenient.
Wave examples: Thomas Youngs double slit experiment
ELEC308 (Spring 2008)
Midterm
TA solution
Problem 1 Solution:
From the geometry of the prism
= (i1 t1 ) + (t 2 i 2 )
= t1 + i 2
Thus, = i1 + t 2
d
=0
d i1
d
d t 2
d
= 1 + t 2 = 0 , then
= 1
di1
di1
d i1
Using Snells Law, we have
sin t 2 = n sin i 2 , s
ELEC308 Engineering Optics
MID-TERM EXAMINATION
DATE:
March 28, 2008
TIME:
6:30 am 9:00 pm
PLEDGE OF HONOR
On my honor as a student of Hong Kong University of Science and
Technology, I have neither received aid from others nor given aid to
others while ta
Problem 1
Problem 10.6
= , sin =
(a) L L
b
b
; (b) L f 2
b
Problem 10.7
For far field, it must satisfy R >
sin 1 =
b2 b2
,
=
(10 4 m) 2
= 0.02 , so it is far field.
4.619 10 7 m
1 = sin 1 ( ) = 0.26 o so angular width is 21 = 0.52 o
b
b
Problem 2
Probl
Problem 1
Problem 9.9
ay
s
10 4 10 3
s=
= 2.05m
=
a
4.8799 10 7
Problem 9.10
1 red 2 violet
m
m =
, since 1,red = 2,violet ,
=
violet = 390nm
a
a
a
Since y
Problem 2
Problem 9.16
h
h
1
E = mv 2 v = 0.42 10 6 m / s ; = =
= 1.73 10 9 m
2
p mv
s
y = 3.46mm
ELEC308 (Spring 2008)
Assignment 4
TA solution
Problem 1
Problem 2 (problem 3.7 on page 82)
Problem 3
3.14
Total power is 20W; total area at 1.0m = 4 12 = 4 (m 2 ) ;
power 20
I=
=
= 1.56W m 2
area
4
3.19
Problem 4
Problem 5
4.40
From Snells law t = 12.748
ELEC308 (Spring 2008)
Assignment 3
TA solution
Problem 1
Problem 2
Please go through page 250 and 251 of the textbook.
Problem 3
(a).
(b). From part a, we know f 1 = 25cm, f 2 = 50cm , this is the focal length of the
equivalent thin lens of the correspond
ELEC308 (Spring 2008)
Assignment2
TA solution
Problem 1
Problem 2
The matrix of thick lens is
P1
n
d
1 d n
nL
L
L=
P2
n
P
(1 d )
nL
n'
n'
where, n L = 1.5, n = n ' = 1, P1 =
nL n 1
n ' nL 1
PP
1
= , P2 =
=
, P = P1 + P2 d 1 2 =
R1
12
R2
20
nL
24
1
1 5
ELEC308 (Spring 2008)
Assignment1
TA solution
Problem 1
Problem 2
Problem 3
4.21 on page 143
Problem 4
4.22 on page 143
Problem 5
Problem 6
Problem 7
Problem 8
Problem 1
1
. The phase
4R
2
1+
sin
(1 R) 2
2
4R
4n2t cos t
difference is =
and the coefficient of finesse is F =
= 360 and
(1 R) 2
I
1
n2 =1. So t =
I 0 1 + 360 sin 2 2t cos t
(1) Since there is no absorption, T=1-R and
It
=
I0
1
0.9
Normalized transmitt
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ELEC308 (Spring 2007)
Final Exam
TA solution
Solution:
a). As the aperture is placed at the image plane, from the Gaussian formula, we have:
nair n air nair
11
1
+
=
+=
si = 150mm
so
si
fr
75 s i 50
b). Also from the Gaussian formula:
nair n air nair
1
1
ELEC 308 Engineering Optics
FINAL EXAMINATION
DATE:
May 31, 2007
TIME:
4:30 pm - 7:30 pm
PLEDGE OF HONOR
On my honor as a student of Hong Kong University of Science and
Technology, I have neither received aid from others nor given aid to
others while taki
Assignment 7*
May 16, 2008
1. Problem 10.6 and 10.7 on page 514
2. Problem 10.9 on page 515.
3. Problem 10.10 on page 515.
4. Problem 10.25 on page 516.
5. Problem 10.29 on page 517.
6. Probl1m 10.33 on page 517.
7. Prove the grating equation for oblique
Assignment 5b
May 9, 2008
1. A beam He-Ne laser (632.8 nm) is incident on a Fabry-Perot apparatus. Two coated
plates with reflectivity 0.90 are at a distance t=1mm. We assume there is not energy
absorption by the plate. (a) Plot the transmission as a func
Assignment 5a
May 2, 2008
1. Problem 9.9 and 9.10 on page 438.
2. Problem 9.16 on page 438. (Hint: calculate de Broglie wavelength of electron stream
and treat electron as wave).
3. Problems 9.27 on page 440.
4. Problem 9.33 on page 440.
5. Explain the ph
Assignment 4
Due date: April 21, 2008
1. Prove the magnification of a telescope M =
fo
D
and exit pupil size Dex = o . (Note:
fe
M
objective lens is aperture stop.)
2. Problem 3.7 on page 82.
3. Problem 3.14 and 3.19 on page 83.
4. Derive the Fresnel equ
Assignment 3
Due date: March 19
1. Problem 6.20 and 6.23 on page 278-9.
2. Analyze a Tessar lens using matrix method (Figure 6.10 on page 251)
3. Problem 5.34 on page 236. In addition, (1) Solve using matrix method and find
principal and focal planes of t
Assignment 2
Due date: March 10, 2008
1. Problems 6.3 on page 278.
2. Problem 6.4 on page 278. Write the system matrix of the lens and verify the
determinant of the matrix is 1.
3. Problem 6.10 on page 278.
4. Problem 5.36, p.236. Solve the problem using
Assignment 1
Due date: Feb. 27, 2008
1. Problem 4.8 on page 142.
2. Problems 4.11, 4.12 on page 143.
3. Problem 4.21 on page 143. (nwater =1.333) When you swim under water with
swimming goggles, did you notice that everything appears closer?
4. Problem 4.
Assignment5
TAs Solution
Problem 1
9.4
A bulb at S would produce fringes. We can imagine it as made up of a very large number
of incoherent point sources. Each of these would generate an independent pattern, all of
which would then overlap. Bulbs at S1 an
Assignment3a
TAs Solution
Problem 1
(i)
3 1
2
Since 1> 2 >3, the stop is the aperture stop. The entrance pupil (EnP) and the exit pupil
(ExP) are shown in the figure.
(ii)
2
1
Since 1> 2, the L1 is the field stop. The entrance window (EnW) and the exit wi
Assignment1
TA Solution
Problem 1
4.6 sin 58 0 = x / 5.0m , x=4.24m
4.8 At the first mirror, r = i . For the second, ii' = 90 r = 90 i and r' = i' So
r' = 90 i
Problem 2
4.12 2.42 sin = 1 sin 45 0 so = 17 0 , the angular deviation is 450-170=280
4.17 1.3
Assignment 6*
May 14, 2010
1. Problem 10.8 and 10.9 on page 515.
2. Problem 10.11 on page 515.
3. Problem 10.25 on page 516.
4. Problem 10.29 on page 517.
5. Probl1m 10.41 on page 517.
6. Prove the grating equation for oblique incidence is a (sin i + sin
Assignment 5
May 4, 2010
1. Problems 9.4 on page 438.
2. Problem 9.6 and 9.10 on page 439.
3. Problems 9.23 on page 440.
4. Problems 9.27 on page 440.
5. Problem 9.32 on page 440.
6. The refractive index of a dense flint glass is about 1.75. Design an ant