Amber has entered a cross country running series. Each race in the series has a time limit by
which runners must complete the course in order to qualify for the next race.
The first race is 9 km long and must be completed in 50 minutes.
After Amber runs t

1) Find all real solutions of:
4
2
2 x + x =3
2 x 4 + x23=0
4
2
2
2 x 2 x +3 x 3=0
x
( 21)=0
2 x 2 ( x 21)+ 3
( 2 x2 +3 ) ( x 21 ) =0
( 2 x2 +3 ) =0
2
2 x =3
3
x 2=
2
3
x=
2
3
x= i
2
2) Given the complex numbers. Find and simplify
z w
, , zw :
w z
z=5+iw

#1.
From the law of indices;
log 2 10=3 x +5
log 2 105=3 x
3 x=log 2 105
x=
log 2 105
3
x=
3.32195
3
x=
1.6781
3
x=0.5594
-#2.
From the laws of indices
log 10 [ x ( x+3 ) ] =1
log 10 [ x ( x+3 ) ] =1
101=x ( x +3 )
x ( x +3 )=10
2
x +3 x=1 0
2
x +3 x10=0

Math 009 Quiz 4
Name_
Instructions:
The quiz is worth 50 points. There are 10 problems, each worth 5 points. Your score on the quiz will be
converted to a percentage and posted in your assignment folder with comments.
This quiz allows open book and open n

3. The organization that surveyed the employees wanted to know what factors
influenced STRESS so they could take action. To do that a multiple regression
analysis was run that regressed all the items against the STRESS measure to see
which ones had the mo

1.(a)
2 x5 x+ 3
3
2
Multiplying by the LCM of the denominators (6) on
both sides
2 x5 x+ 3
3
2
6*
2(2x - 5)
4 x 10
(x +3)
3
3x + 9
4x 3x
X
*6
9+10
19
[19,)
1.(b)
|7 4x| < 3
Forming a double inequality out of this
-3 < |7 4x| < 3
Subtracting 7 from all th

#1.
Dividethrough by cosx
sinx
=1
cosx
tanx=1
1
x=tan ( 1 )
x= +k .
4
For the given interval ( 0,2 ) , we substitute k=0,1
x=
k =0,
k =1,
x= +
4
#2.
sin ( 2 x )=cos ( x)
=>
x=
5
4
4
Using the Double Angle Concept
sin ( 2 x )=2 sinxcosx
Therefore
2 sinx

Forbothproblems,showsupportingworkandunderlineyouranswer.PleaseuseMathType.
1.) Findthesecondderivativeoff(x)=(4x+5)4andevaluateitatx=3.
f ( x )=(4 x +5) 4
We first need expand the brackets
f ( x )=( 4 x4 ) + ( 54 )
f (x)=16 x +20
Then compute the first

1 1
+ =1
x y
1. Y=f(x) and
Find
1
f (x)
Make y the subject
1
1
=1
y
x
1 x 1
=
y x x
1 x1
=
y
x
We do n' t even need express terms of x ,
w e already have what is needed .
1 x1
f 1 ( x )= =
y
x
2. Solve the following equation in the interval
[ 0,2 )
x
si