Physics 105
Spring 2011
HW #1 Solutions
Q6) The net charge on a conductor refers to the difference between the number of
protons and the number of electrons. Neutral: difference =0; Positive: more pro
Physics 105
Spring 2011
HW #5 Solutions
Ch. 19
Q5) The outlets in a double outlet are connected in parallel. Both outlets deliver the
same potential difference of 120 VAC and they operate independentl
Physics 105
S2011
HW 4 Solutions
Ch 17
P32) Q = CV, so V = Q/C=16.510-8 C/950010-12 F = 17 V.
P39)
E = V/d. Know d, but need V. Use Q = CV so V = Q/C = 7210-6 C/0.8010-6 F = 90 V.
Thus E = 90 V/0.002
Physics 105
Spring 2011
HW #3 Solutions
Ch 17 Questions
Q6) Yes. A particle with a negative charge moving from lower potential
to higher potential will have its potential energy decrease. For example
Physics 105
Spring 2011
HW #2 Solutions
Ch 16
Q14) A negative charge can be used to determine the electric field. The
"
magnitude of E is still
"
F
, but the direction of E is opposite to the directio
Physics 105
Spring 2011
HW #6 Solutions
Ch. 19
Q19) No, the total energy supplied by the battery is not stored in the capacitor. Some of the
energy is dissipated as heat, as the charge flows from the
Physics 105
Spring 2011
HW #7 Solutions
Ch. 20
Q8)
The kinetic energy will stay the same. The force on the charged particle due to the
magnetic field is perpendicular to the direction the particle is
Physics 105
Spring 2011
HW 12 Solutions
1) Ch23 P31
The angle between the light beam and the surface of the pool is given by tan = 1.3/2.7.
This gives = 25.7. The angle of incidence is 90 - 25.7 = 64.
Physics 105
Spring 2011
HW 11 Solutions
Part 1
Ch. 23 P72
a) Image 1: The closest image is the one you see looking in any single mirror. Since
you are 1.5 m from the mirror, the image appears 1.5 m be
Physics 105
Spring 2011
HW 10 Solutions
1) a) C =
"0 A
. A = r2 = 0.0038 m2. D = 0.025 m. C = 1.36 10-12 F.
d
b) Q = CV = 3.4 10-10 coulombs.
!c) E = V/d = 250/0.025 = 10,000 V/m.
d) Flux through left
Physics 105
Spring 2011
HW #8 Solutions
Ch. 21
Q6)
a)
The current moves through RB from right to left. Using the right hand rule for
solenoids, the left side of coil B is a north pole. Over by coil A,
Physics 105
Spring 2011
HW #9 Solutions
1) a) FT = mg = .00444 kg 9.80 = 0.0435 N
b) Since the tension decreases, the force on the sphere due to the electric field must be up.
Since the sphere has a n
Waves and Fields (PHYS 195): Week 6
Spring 2014 v1.5
Intro:
Well be studying the wave properties of sound. Most of the wave behavior is the same as on waves on
a string but there are some dierences. O
Waves and Fields (PHYS 195): Week 5
Spring 2014 v1.5
Intro:
This week start studying waves, beginning with transverse waves on a string and basic properties of
waves. We will work toward nding the equ
Waves and Fields (PHYS 195): Week 3
Spring 2014 v2.0
Intro:
This week we begin to study how the dynamics of oscillation changes due to damping. Then we will
add driving forces and encounter the phenom
Waves and Fields (PHYS 195): Week 2
Spring 2014 v2.1
Intro:
We will see on Wednesday (January 29) how all conservative systems exhibit SHM around equilibrium.
Our study of oscillation continues with a
Waves and Fields (PHYS 195): Week 1
Spring 2014 v2.0
Intro:
Our course starts with an in-depth study of oscillations: motion that returns to the same place at
the same momentum. The tools are familiar
Waves and Fields (PHYS 195): Week 4
Spring 2014 v1.0
Intro:
This week we nish our study of damped driven oscillators - and resonance. Next week well start on
our study of waves, beginning with transve
Waves and Fields (PHYS 195): Week 8
Spring 2014 v1.5
Intro:
We will develop of the theory of static electric elds. Before break we will discuss Coulombs law,
the electric eld, and the close analogy wi
Waves and Fields (PHYS 195): Week 7
Spring 2014 v1.0
Intro:
We have a bevy of aspects of waves to discuss, beats, interference in space, intensity and Doppler Shift.
Then it is onto elds! We will stud
Waves and Fields (PHYS 195): Week 9
Spring 2014 v1.5
Intro:
This week we nish our discussion of electric potential and electrostatics before moving on to a bit of
magnetostatics.
Reminder: We have Mid
Waves and Fields (PHYS 195): Solutions 2
Spring 2014 v1.0
Solutions:
(1) A suitably winterized right whale:
(a) F = ma gives kx = md2 x/dt2 which, expressed in standard form is
k
d2 x
d2 x
+ x = 0 or
Waves and Fields (PHYS 195): Solutions 7
Spring 2014 v1.0
Solutions:
(1) Fourier series by guess work:
(a) There are a number of dierent games so you might have dierent sketches. Heres the
one I worke
Waves and Fields (PHYS 195): Solutions 3
Spring 2014 v1.7
Solutions:
(1) Sine approximation
(a) Since all the derivatives are either sine or cosine and since we evaluate at 0, only the cosine
terms su
Waves and Fields (PHYS 195): Solutions 8
Spring 2014 v1.0
Solutions: There are a total of 3 possible Bonus points
(1) The intensity falls o as the surface area of the spherical wavefront. So for part
Waves and Fields (PHYS 195): Solutions 6
Spring 2014 v1.0
Solutions:
2
(1) Practice with partials for u = ex + 2xy 2 .
(a)
2
u
= 2xex + 2y 2
x
(b)
u
= 4xy
y
(c)
2u
2u
=
= 4y
xy
yx
So they are equal, w
Waves and Fields (PHYS 195): Solutions 1
Spring 2014 v1.0
Solutions:
(1) (Taylor 2.3)
(a) Too many sig gs in the uncertainty. It should be h = 5.03 0.04 m.
(b) A silly number of sig gs in the best est
Waves and Fields (PHYS 195): Solutions 4
Spring 2014 v1.8
Solutions:
(1) Phet spring sim: Using the 250 g mass on the third spring (set at 7 on the softness scale) I
observed an extension of 16.8 cm.