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Magnetism
Page 853 # 11
_
Page 853 # 17
The energy of the proton is a kinetic energy so it is equal to
(
)
Newtons second Law:
P 855 #37
We wont consider the effect of rotation of the rod (The correct solution is to take the effect of
rotation, but I sup

Thursday, Nov 10th, 2011
Allowed time: 1 hour
Physics I for Scientists, Phys 211 Section 2
(Coulomb constant ke = 9 109 N.m2/C2)
l
Problem 1:
(a)
2a
a
A solid cylindrical conductor of radius a and charge Q is coaxial with
a cylindrical shell of negligible

Homework # 2
P 705 # 4
60
30
60
a) The electric flux through the rectangular surface is:
= . = . . = . |. cos 180 = = = 7.8 104 0.1 0.3
= 2340 . 2 /
b) The electric flux through the slanted surface is:
= . = . . = . |. cos 60 = 0.5 = 0.5 = 0.5 7.8 104

Physics for engineers, Phys 211, section 2
Fall 2012, exam1
y
Problem 1:
P
A ring of radius R has a uniformly linear charge density
y
a) Calculate the electric field due to the ring at a point P lying a distance
y from its center along the central axis p

Physics for engineers, Phys 211, section 1
Fall 2012, exam1 + Solution
Problem 1:
a) A thin rod of length and positive uniform charge per unit length lies along the x-axis.
Show that the electric field at P, a distance /2 from the rod along
its perpendicu