07APR2009
HOME PROJECT 6/FINAL EXAM PROJECT
THE PARTLY DIRECTED SQUARE AND T IN
THE CONTINUOUS CASE
DUE BEFORE WEDNESDAY 05.MAY.2009
Consider the two simple acyclic mixed graph M1 (V, E1 ) and M2 (V, E2 ) dened in the
pictures below:
1
2
a
2
b
a
b
1
M1
M2
02MAR2009
TAKE HOME MIDTERM EXAM
MARGINAL AND CONDITIONAL INDEPENDENCE
THE CONTINUOUS CASE
DUE WEDNESDAY 01.APR.2009
This exam is similar but a bit more complicated than the earlier Homework 1 on the continuous
case. Nevertheless it will be easier to solv
22JAN2009
ANSWERS TO HOMEPROJECT 1
SIMPLE ONE DIMENSIONAL MARGINAL INDEPENDENCE
DUE WEDNESDAY 04FEB.2009
This homework assignment is similar to the Part 1 of the lecture notes from 21JAN.
The model herein is a special case of the three vertex graphical mo
30JAN2009
ANSWERS TO HOMEPROJECT 2
SIMPLE ONE DIMENSIONAL MARGINAL INDEPENDENCE
THE DISCRETE CASE
DUE WEDNESDAY 18FEB.2009
This homework assignment is similar to the Part 2 of the lecture notes from 21JAN.
The model herein is similar to Homeproject 1, a s
16FEB2009
ANSWERS TO HOMEWORK 3
CONDITIONAL INDEPENDENCE
DUE WEDNESDAY 04MAR2009
Recall the notation from the lecture notes:
Let = (v |v V ), where V is a nite set and v is a measurable space. Let P be a probability
measure on , i.e., P P (), and let A, C
25FEB2009
ANSWERS TO HOMEPROJECT 4
MARGINAL AND CONDITIONAL INDEPENDENCE
THE DISCRETE CASE
DUE WEDNESDAY 18.MAR.2009
This homework assignment is similar but a bit more complicated than the earlier Homework 2 on
the discrete case. Nevertheless it will be e
07APR2009
SOLUTIONS TO HOMEPROJECT 5
THE SQUARE IN
THE CONTINUOUS CASE
DUE BEFORE WEDNESDAY 05.MAY.2009
Consider the simplest NON-decomposable undirected graph U (V, E ) dened in the picture
below.
2
a
b
1
Thus the vertex set is given by V := cfw_1, a, b,
07APR2009
SOLUTION TO HOME PROJECT 6/FINAL EXAM PROJECT
THE PARTLY DIRECTED SQUARE AND T IN
THE CONTINUOUS CASE
DUE BEFORE WEDNESDAY 05.MAY.2009
Consider the two simple acyclic mixed graph M1 (V, E1 ) and M2 (V, E2 ) dened in the
pictures below:
1
2
a
2
b
02MAR2009
SOLUTIONS TO THE TAKE HOME MIDTERM EXAM
MARGINAL AND CONDITIONAL INDEPENDENCE
THE CONTINUOUS CASE
DUE WEDNESDAY 01.APR.2009
This exam is similar but a bit more complicated than the earlier Homework 1 on the continuous
case. Nevertheless it will