Testing of Gas Wells
Drawdown and Buildup test can be also performed on gas wells. To analyze the well test data from
gas well the flow equations must be modified for gas as was discussed in Chapter 5. The infiniteacting solution for gas well can be writt
PNGE 333
SPRING 2011
Homework 3
The plugs from the core sample in Homework 2 were analyzed through conventional analysis. In Homework 2,
you determined the porosity and permeability of each core plug.
The following steps have been also taken during the ex
Log of Porosity vs Log of Formation Resistivity
3
2.5
Log of Format ion Resist ivit y
f(x) =  2.0000063926x  7.77149050311975E006
R = 0.9999999997
2
1.5
1
0.5
1.25
1.2
1.15
1.1
Log of Porosit y
1.05
1
0
0.95
Finding n from Core Analysis
0.65
0
PNGE 333 SPRING 2007
HOMEWORK 4 Solution
Problem 1
Solution Method
Bulk volume = r 2 h
Pore volume = Vb
V
V
S w = w , So = o , S g = 1 So S w
Vp
Vp
Results
2
Bulk volume = r 2 h = (1.25) (3) = 14.73cm 3
Pore volume = Vb = 0.27(14.73) = 3.98cm 3
1.20
Sw =
Homework #12
Petroleum and Natural Gas Engineering 333
Elements of Petroleum Reservoir Engineering
4/17/07
James R. Odom Jr.
Petroleum and Natural Gas Engineering
West Virginia University
1.) Calculate the water influx at the end of 5th and 6th quarter of
Homework #8
Petroleum and Natural Gas Engineering 333
Elements of Petroleum Reservoir Engineering
3/10/07
James R. Odom Jr.
Petroleum and Natural Gas Engineering
West Virginia University
1.) Wells 1 and 2 are drilled 2,500 feet apart in an undeveloped res
SPRING 2007
PNGE 333 HOMEWORK 1
1. The following PVT data are available from an oil reservoir.
A)
What volume SCF of gas per stocktank oil is released when the pressure
decline
from 1700 to 1300 psia?
B)
Calculate the gas volume in part (A) at 1300 psia
Homework #11
Petroleum and Natural Gas Engineering 333
Elements of Petroleum Reservoir Engineering
4/6/07
James R. Odom Jr.
Petroleum and Natural Gas Engineering
West Virginia University
1.) An oil reservoir after one year of production has produced 253,5
PNGE 333 SPRING 2007
HOMEWORK 5 Solution
Solution Method
1. Determine porosity from the density log data using:
ma=2.68 g/cc and f =1 g/cc
2.68
ma
1
D = ma = 2.68 = 1.68 (2.68 )
1
fl
Results:
Well A
Depth
ft
4000.5
4001.5
4002.5
4003.5
4004.5
4005.5
40
PNGE 333
Home Work #2
James R. Odom Jr.
West Virginia University
1/20/07
1. The following information is available from a series of measurements on a core
sample:
g
cc
g
bulk 2.28
cc
g
fluid 1.0
cc
grains 2.6
bulk is the density of the core sample whe
PNGE 333
Homework 9
Chelsie Hupp
3/23/07
1. The discovery well in a new reservoir was produced for 24 hours at a rate of 5000
MCF/D and the pressure was recorded. The test results and other relevant data are
provided below. Determine k and s.
h=22 ft
pi=1
Homework #11
Petroleum and Natural Gas Engineering 333
Elements of Petroleum Reservoir Engineering
4/6/07
James R. Odom Jr.
Petroleum and Natural Gas Engineering
West Virginia University
Homework #10
A gas reservoir is under study for development. The map
PNGE 333
SPRING 2007
HOMEWORK 1Solution
Problem 1
A
Solution Method
Gas Released = ( Rs )1700 ( Rs )1300 SCF / STB
Calculations and Results:
Gas Released = ( Rs )1700 ( Rs )1300 = 540 440 = 100 SCF / STB
B
Solution Method
Gas Released, ft @ 1300 psia = S
PNGE 333
SPRING 2007
Homework 9 Solution
Problem 1
Solution Method
2
1. Plot Pwf vs. t
2. Determine m and p12hr
1637T zq
mh
p 2 p12hr
k
4. Caculate : s ' = 1.151 i
log
+ 3.23
2
ct rw
m
k =
3. Caculate :
Results
t
1
2
3
4
5
6
7
8
9
10
15
20
24
Pw
PNGE 333 SPRING 2007
HOMEWORK 7 Solution
Problem 1
Solution Method
The formation face pressure can be evaluated from:
pwf = pi  162.6
kt
qB
log
 3.23 + 0.87 s
2
kh
c t rw
Results:
ct = co So + cw S w +cg S g +c f = 18 10 6 ( 1 0.35 ) + 3 10 6
Homework #5
Petroleum and Natural Gas Engineering 333
Elements of Petroleum Reservoir Engineering
2/14/07
James R. Odom Jr.
Petroleum and Natural Gas Engineering
West Virginia University
The following information is available on three wells in a newly dis
Solution Method for porosity determination
e = (b s) / (f s) ,
Vb = (Wsat Wim) / f ,
a = (1 (Vs/Vb)* 100
s = Wd/Vs ,
b = Ws/Vb
Result:
The results are display in table I
Solution method for permeability determination
Kair = (2q2*L*P2) / (A*(P1^(2) P2^(2
PNGE 333
SPRING 2010
Homework 4
The attached well log data were obtained from the well #1 as described in Homeworks 2 and 3 .
samples from well #1 are also provided.
Additionally, the well log data were obtained from 4 other wells (#2,#3 ,#4,and #5) in th
PNGE 333
Homework # 4
Armel Mbakop
02/23/2011
Homework 5
Determine the initial gasinplace for a reservoir with the information given.
Solution Method
1. Determine the porosity and water saturation from well log data according to the results of
Homework
PNGE 333
Homework # 4
Armel Mbakop
02/16/2011
Question # 1:
Determine porosity and water saturation for each well from the well log data assuming:
= 2.68 g/cc, f = 1 g/cc and Rw= 0.05 ohm.m
Solution Method:
D =
b
ma
/
f

ma
= 1 /1.68 (2.68 
),
b
SW =
PNGE 333 Exam
Time: 60 Minutes
A gas reservoir has a discovery pressure of 3200 psia and a temperature of 213 oF. The seismic
maps indicate that the structure of the gas sand has a bulk volume of 41510 6 ft3. Porosity is
estimated to be 17.2%, connate wa
PNGE 233
SPRING 2001
EXAM II
Problem 1 (40 points)
The permeability of a core sample 1inch in diameter and 1inch long was measured using
air ( = 0.02 cp). The following data were obtained during the experiments. Determine the
permeability of the core sa
Lecture 2
PNGE333
PNGE 333
Reviewoff
FluidProperties
p
Fluids
FLUIDS
Solid
Themoleculesareheldinplace
bystrongforces.
Liquid
Gas
Themoleculesareheldtogether
byweakforces.
M h i lP
MechanicalProperties
ti
Solidscanpermanentlyresistverylargeshearforces.
Flu
Objective
The objective to Experiment No. 12: Surface and
Interfacial Tension Measurements is to determine surface
and interfacial tensions by the du Nouy method.
Procedure
After the tensional instrument has been calibrated, the
experiment will begin by f
t
days
0
365
N=
P
Bo
Rs
Bg*103
Np
Gp
Wp
We
Psia
2500
2400
RB/STB
1.498
1.463
SCF/STB
721
669
SCF/STB
1.048
1.155
MSTB
0.0
273.8
MMSCF
0.0
246.4
MMbbl
0.000
0.000
MMbbl
0.0
0.202603
N P Bo + Bg GP  N P Rs  G Bg Bgi  We WP
Bo
Boi + Rsi Rs Bg
AQUIFER