COLLEGE OF ENGINEERING
PUTRAJAYA CAMPUS
FINAL EXAMINATION
SEMESTER 1 2010 / 2011
PROGRAMME
: Bachelor of Electrical and Electronics Engineering
(Honours)/ Bachelor of Electrical Power Engineering
(Honours)
SUBJECT CODE
: EEEB233
SUBJECT
: Signals and Syst

Week 6 Lecture
Example of a second order LCCDE (A real system commonly found in electrical
engineering)
The circuit shown below is an example of a second order Linear Constant Coefficient
Differential Equation.
The input x(t) is the voltage source and the

UNIVERSITY TENAGA NASIONAL
DEPARTMENT OF ELECTRICAL AND ELECTRONICS ENGINEERING
Signals and Systems
Part 0
Review
COMPILED BY WONG HUNG WAY
November 2010
1
1. Review of Complex Numbers
2. Review of Continuous Time Complex Exponential and Sinusoidal
Signal

Week 8
Calculate the Fourier series coefficients of the periodic signal x(t) as shown below
X(t)
-2
0
=
6
2
2
First we find a0
1
2
. 0 = 2 .
1
2
Since T= 6, 0 = 6 2 .=
4
6
3
Alternatively, instead of performing the integration we can find a0 as
a0 is simp

Week 5 Lecture
Signal Decomposition
A unit sample can be used to decompose an arbitrary signal x[n] into a sum of weighted and
shifted unit samples i.e
. x[3] n 3 x[2] n 2 x[1] n 1 x[0] n x[1] n 1 x[2] n 2 x[3] n 3.
This decomposition can be written in a

Week 9 Lecture
Example 1
Calculate the Fourier series representation of the signal shown
X(t)
-2
-4
2
0
4
The period T = 2
1
1
1
Using the analysis equation = 2 () 0 = 2 1 () 0
=
This means =
1
2
2
1 1
1 1
1 1
1
() 0 = () 0 = () =
2 1
2 1
2 1
2
for all

Week 7 Lecture
Fourier Series
If given a continuous time signal x(t), and if x(t+T) = x(t), then the signal x(t) is said to be a
periodic signal, with period T.
The signal complex exponential x(t ) A exp j0t is periodic with period T
2
0
, because
x(t T

Week 11 Lecture
The Discrete Time Fourier Transform (DTFT)
Representation of Aperiodic Discrete Time Signals Using The Discrete Time Fourier
Transform
The Discrete Time Fourier Transform of an aperiodic discrete time signal is an extension
of the Fourier

Solution to Test 1 (August 2009)
Question 1
The system is given as y(n)=nx(n-1)
a) The system is a memory system because the output y(n) at the nth sample sequence
depends on the input x(n) other than the nth sample sequence. Eg at sequence n=1, the
outpu

Solution to Test 1 (16 August 2010)
Question 1a
The system is given as y(t)=tx(1-t)
a) The system is a memory system because the output y(t) at time t depends on the input
other than the time t. Eg at time t=0, the output y(0) depends on x(1).
[2 marks]
b

EEEB233 : SIGNALS AND SYSTEMS
SEMESTER I 09/10
TEST 1
50 Minutes (5TH AUGUST 2009)
Question
Name
:
1
ID No.
:
2
Section
:
Marks
3
Total
Reminder:
1. Do not open the question paper until you are instructed to do so.
2. Answer all questions. Show all your w

Signals and Systems EEEB 233
Week 1 Lecture
Classification of signals
There are 2 broad classes of signals i.e (i) continuous time signal (CT) and (ii) discrete time signal (DT)
i) Continuous time signal. The x axis represents the continuous time t . t is

Signals and Systems EEEB 233
Week 2 Lecture
Plotting of Continuous Signals and their Manipulation in Time
(i) Flipping in Time
Consider a continuous time signal f(t) given as shown.
3
-2
0
2
What is f(-t) ?. When you want to plot f(-t), follow these 3 sim

COLLEGE OF ENGINEERING
PUTRAJAYA CAMPUS
FINAL EXAMINATION
SEMESTER 1 2009 / 2010
PROGRAMME
: Bachelor of Electrical and Electronics Engineering
(Honours)/ Bachelor of Electrical Power Engineering
(Honours)
SUBJECT CODE
: EEEB233
SUBJECT
: Signals and Syst

Week 10 Lecture
The Fourier Transform
In the previous lectures, we discussed the Fourier Series, which is for periodic signals.
This lecture will cover the Fourier Transform which can be used to analyze aperiodic
signals (aperiodic means non-periodic). Fo

Solution to Test 1 (January 2010)
Question 1
The system is given as y(t)=tx(t-1)
a) The system is a memory system because the output y(t) at time t depends on the input
other than the time t. Eg at time t=0, the output y(0) depends on x(-1).
b) The system

EEEB233 : SIGNALS AND SYSTEMS
SEMESTER I 09/10
TEST 1
90 Minutes (16TH AUGUST 2010)
Question
Name
:
1
ID No.
:
2
Section
:
Marks
3
Total
/60
Reminder:
1. Do not open the question paper until you are instructed to do so.
2. Answer all questions. Show all y

Signals and Systems (EEEB233) Tutorial 4 (Due 28 August 2015 5.30 pm)
Question 1
Given a signal x(t ) 3 2cos 3 t 3sin 4 t , find its Fourier series coefficients.
3
Calculate the total average power of x(t).
Question 2
t
t
Given x(t ) 2sin 3cos , calcu

Solution to EEEB233 Final Exam (April 2011), Semester II 2010/2011
Question 1
a)
Since the given signal
n
n
n
sin 2 cos
4
8
2
x[n] cos
,
You can imagine that x[n] consist of 3 discrete time periodic signals of
x1[n] cos
n
4
with angular freque

COLLEGE OF ENGINEERING
PUTRAJAYA CAMPUS
FINAL EXAMINATION
SEMESTER II 2010 / 2011
PROGRAMME
: Bachelor of Electrical and Electronics Engineering
(Honours)/ Bachelor of Electrical Power Engineering
(Honours)
SUBJECT CODE
: EEEB233
SUBJECT
: Signals and Sys

COLLEGE OF ENGINEERING
PUTRAJAYA CAMPUS
FINAL EXAMINATION
SEMESTER 1 2010 / 2011
PROGRAMME
: Bachelor of Electrical and Electronics Engineering
(Honours)/ Bachelor of Electrical Power Engineering
(Honours)
SUBJECT CODE
: EEEB233
SUBJECT
: Signals and Syst

COLLEGE OF ENGINEERING
PUTRAJAYA CAMPUS
FINAL EXAMINATION
SEMESTER 2 2009 / 2010
PROGRAMME
: Bachelor of Electrical and Electronics Engineering
(Honours)/ Bachelor of Electrical Power Engineering
(Honours)
SUBJECT CODE
: EEEB233
SUBJECT
: Signals and Syst

Signals and Systems EEEB 233
Week 3 Lecture
Systems
A system is a mathematical model of a physical process that relates the input signal (excitation) to the
output signal i.e y(t) =T(x(t). T is the operator representing some defined rule by which x(t) is

EEEB233 : SIGNALS AND SYSTEMS
SEMESTER II 09/10
TEST 1
50 Minutes (8TH JANUARY 2010)
Question
Name
:
1
ID No.
:
2
Section
:
Marks
3
Total
Reminder:
1. Do not open the question paper until you are instructed to do so.
2. Answer all questions. Show all your