Ashford 2 : MATT222- Week 2 - Quiz
Question 1. 1. In the slideshow, Absolute Value Equations located in Chapter 8,
the first step in solving an absolute value equation is _. (Points : 1)
Rewrite the e
-12 2 + 2x 10
-12 2 + 2x - - - First separate both parts of the equation.
& 2 + 2x 10
-12 2 + 2x - - - Put all real numbers on one side of the , and variables on
the other.
-2
-2
-14 2x
&
2 + 2x 10 -
Ashley Jackson
Number - 15
2
4 k 12 k +9
4k
4k2
4k
4k2
4k
= k
12 k
4k
- - - First, share the denominator with each part of the numerator.
9
+ 4k
- - - Next, divide each one.
12 k
4k
9
= 3
9
+ 4k
= + 4
1
9 3
#60: w
Starting with this problem, Ill multiply the nth power outside of the parenthesis against the
number that is inside the parenthesis:
9 1
x
9
w 1 3 =w 3
3
After multiplication is done we
#32 & 44 on 575-577 and 584-585
Simplify each expression using the rules of exponents and examine the steps you are taking.
Incorporate the following five math vocabulary words into your discussion. U
22 7 < 2x 5 4
8x 4 > 6 or 3x + 18 6
The first compound inequality that I was assigned is -7 < 2x 5 < -4.
-7 < 2x -5
I will do the left side first.
2x 5 > -7
I switched sides to make it easier.
2x 5 +
22 7 < 2x 5 4
8x 4 > 6 or 3x + 18 6
The first compound inequality that I was assigned is -7 < 2x 5 < -4.
-7 < 2x -5
I will do the left side first.
2x 5 > -7
I switched sides to make it easier.
2x 5 +
x2 + 6x + 8 = 0 4 on p. 658
Factoring
Quadratic formula
For the factoring problem, be sure you show all steps to the factoring and solving. Show a
check of your solutions back into the original equati
A domain is a set of numbers that replace variables in a function. The denominator cannot be zero
because it would be considered undefined, therefore resulting in an illegal fraction.
#22
FIRST PROBLE
Question11pts
Afterviewingtheexampleintheslideshow,QuadraticFunctions,inthemediasectionof
Chapter11,thepresenterusesthefollowingtographthequadraticfunction:
vertex and intercepts
slope and domain
slop