My first equation,
The starting point of this function, when graphed is at 0,0 with the parabola pointing downwards.
The domain cfw_xxR )( ,
(Section 7.1 7.3, 8.1 8.3)
Introduction System of Equation
In MAT 221, we learned solving system of equation involving just one
equation and one variable. Examples of such equations are 2x + 10 = 25 or
x2 2x + 1 = 0.
Week 1 Discussion Post
A rational expression is of the form:
3 3x 2
4 2x 1
Now, rational-expression cannot have zeros in the denominator. A zero will make the
expression undefined. Why? Lets try to unde
The first step -2/3 as a product.
The next step would be to Simplify.
Turn 27 using principal root 33
So now we have (33)1/3)2
Next multiply exponents
And get rid of the
My assigned number was 24. So my first expression is y2 25
So since the denominator of this rational expression included a real number it means the domain
will be a real number. I found this out because if I factor in 0 the domain is infinite. But if I
Hello Class my assigned number is 25.
My first problem is:
2 x 2 -x-3=0
The first step is factoring the left side of the equation.
( 2 x3 )( x +1 )=0
In which we get 2x minus 3 and x plus 1 is equal to 0.
The discriminant for the equation being a=2 b=1 c=
Explain in your own words what the meaning of domain is. Also, explain why a denominator cannot be
Find the domain for each of your two rational expressions.
Write the domain of each rational expression in set notation (as demonstrated in the exampl
3a + 16a +5
a - 7a + 10
To find the domain, i.e. the set of values that can possibly be plugged in for the variable, we
must first isolate all the values that we know it cannot be. These are called excluded values.
Because the denominator cannot be zer
One-Variable Compound Inequalities
For my and compound inequality, I was given: 9 5 + 2x 19
In this type of problem both mathematical statements must be satisfied for the expression to
valid. I can begin solving by splitting the problem into these two
One Variable Compound Inequalities
As my assigned number is 18, my first problem for this weeks discussion is 5 </= - 3x 2 < 8.
Because this is an and problem, both components of the inequality must be satis
x + 3x 18 = 0
To solve this problem by factoring I must first find the two numbers whose products are -18 and
sums are 3. The obvious choices are 6 and -3.
(x + 6) (x - 3) = 0
x = -6 or
To check the solution, I plu
For this assignment, the first of the two problems that I was assigned was #88. This
Because the bases are dissimilar we use the product rule i.e. (a b) = a b + a b. This
(3 9) Or
For the second problem I w
74. (2a )6
To begin working this problem, I am first going to use the Power Rule to distribute the .
Once the exponent has been distributed I can use the power rule to eliminate the factions.
6 is a multiple of both and so the f
A card is selected from a deck. Find the following probabilities.
A standard deck of cards has 52 Cards. There are 13 values and 4 suits. Suits are Spades, Clubs, Diamonds and Hearts. Each suit has 13 cards. There are 3 face cards Jack, Queen, and King.
A credit card company charges 18% interest on the unpaid balance. If you owed $2000 three months ago and have been delinquent since, how much do you owe? 1.045
I=Prt. I=$2000(.18)(3/12). I=$90. Add the interest to how much you owed: $2000+$90=$2,090. This
MATH 106, SUMMER 2017 QUIZ 5
(1) A standard deck of cards has 52 cards in it. The cards are divided into 4 suits or 13
cards each.If one draws two cards at random from the deck of cards what is the
probability that they are of the same suit ?
13/52 * (13-
(1) A chemist wants to mix two kinds of glycerins for the manufacture of a soap. The
glycerin from supplier A cost $1 million per ton and the glycerin from supplier B costs
$1.5 million per ton. The chemist is obligated to buy no more than twice as much
Solve the inequalities for the following exercises. Express solution set using interval notation,
and graph the solution set on a number line (see Content > Course Resources > Webliography to
see how to create a number line in a word-processin
Solve the inequalities for the following exercises. Express solution set using interval notation, and graph
the solution set on a number line (see Content > Course Resources > Webliography to see how to create
a number line in a word-processing app
UMUC MATH 106, SUMMER 2017 QUIZ 6
(1) The height of the workers (in cm) in an oce is
87,173,165 Plot a histogram of the heights of the workers.
(2) What is the mean, mod
(1) Find the equation of the line which passes through the point (2,4) and (3,3)
y = mx + b to calculate the equation
m = y2 - y1
x2 - x1
(2) Find the equation of the line with slope 3 which passes through the point (1,1)
y = mx + b
m is the slope,
On this weeks discussion, I was assigned # 12. The first problem that I am to solve is
x x=0 to start
solving this I need to factor the GCF (Greatest Common Factor). The resulting term is a product of the GCF and
the original expression divided by the G
I was assigned number 16 for this weeks discussion. I am not the best at this, but will give it my all. So, the
problems that I have for number 16 is:
5m2 + m /m + 6 and 12a 15/5a 25 I will attempt to do the first one as follows.
So, I take 5
For this weeks discussion, I was assigned number 12, I am to solve by graphing and state the domain and
range. The first equation is
y=x 2 x3 which is located on page 711 in our eBook.
First I need to bring this equation to a graphable form, and move al
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HCA 340- Managing in Health and Human Services
Instructor Lilia C
1. Question :
In the video,
Exercise 71: Domain and Range, located in the media section of
Chapter 11, the presenter states that the range of her three points
all real numbers
1 of 1
1. Question :
In the video, Example 7, Using the quadratic formula: Integer
coefficients, which is located in the media section of Chapter 10,
the presenter solves the quadratic formula resulting in these two
z = 3/2 and z = 1/3
1. Question :
When looking at the problem given in the slideshow, Using the
Rules of Exponents, located in the media section of Chapter 9,
why can we not use the Product Rule to simplify the expression?
The exponents are different.
1. Question :
In the Video: Extraneous Solutions, located in the media section
of Chapter 6, the solution of 3 is an extraneous solution in the
1 of 1
1. Question :
After viewing the video, Exercise 21 Solving by Substitution:
Independent, in the media section of Chapter 7, the presenter
suggests plugging y = 2 into the first equation. If you substituted
y into the second equation your answer will be in