Lesson #7: Branching Pipe Systems
3-Reservoir Problem
Assuming that minor losses are negligible and that the friction factors in all the pipes are
constant (f = 0.024), compute the flow (Q) in each pi
Lesson 19: Flow Profiles and Natural Channels
Example Problem
The compound channel shown below has a channel slope (S0) of 0.004 m/m. The water
depth (y), as measured from the main channels bed, is 3
Lesson #4: Frictional Resistance
Head Loss Example Problem
A 50 mm diameter commercial steel pipe (ks = 0.046 mm) has a length of 100 m. Find
the head loss (in m) for water for the two discharge rates
Lesson #5: Minor Losses and Grade Lines
Energy Losses in a Pipe System
Water flows from reservoir 1 to reservoir 2 in an 8-in diameter, 600-ft long pipeline.
Determine the velocity (in ft/s) assuming
Lesson #7: Branching Pipe Systems
3-Reservoir Problem
Assuming that minor losses are negligible and that the friction factors in all the pipes are
constant (f = 0.024), compute the flow (Q) in each pi
Lesson 12: Hydraulic Transients
Water Hammer Example
The velocity of flow in the pipe segment is 2 m/s when a valve is closed suddenly. The
temperature of the water is 20C.
Reservoir
Valve
Pipe Segmen
Lesson 14: Open Channel Flow Equations
Mannings Equation Example
A rectangular open channel has bottom width (b) of 4 ft and a slope (S0) of 0.001 ft/ft.
The channel is constructed out of concrete.
a)
Lesson 15: Specific Energy & Critical Depth
Critical Depth for a Rectangular Channel
The rectangular channel shown below has a discharge rate of 2 m3/s.
Find the critical depth yc (the depth where the
Lesson 18: Classification of Water-Surface Profiles
Example Problem
A rectangular channel with a 10 m bottom width has a slope of 0.01 and a Mannings
coefficient of 0.025. For a flow rate of 50 m3/s,
Lesson 19: Flow Profiles and Natural Channels
Example Problem
The compound channel shown below has a channel slope (S0) of 0.004 m/m. The water
depth (y), as measured from the main channels bed, is 3
Lesson 20: Computation of Water-Surface Profiles
Direct-Step Method Example
A rectangular channel with a 5 m bottom width has a slope of 0.005 and a Mannings
coefficient of 0.030. For a flow rate of 5
Lesson 26: Frequency Analysis
Flood Probabilities
On Fourmile Creek, the 1993 flood produced the 6th largest peak discharge in the 21-year
streamgage record. What is the estimated return period T (in
Lesson 28: Rational Method
10-Year Design Flow Using the Rational Method
Compute 10-year design discharge on an Iowa City creek for culvert design:
A = 100 acres
C = 0.35 (Single family residential fo
Lesson 30: Streamflow Prediction
Rainfall Excess Prediction Using the -Index
Given
Incremental rainfall hyetograph
= 0.6 in/hr
Watershed area A = 1 mi2
Find
Infiltration (rate f and incremental acc
53:071 Principles of Hydraulics & Hydrology
Exam 1 (Closed Conduit Flow)
Spring 2010
Name: _
Equations and constants you may (or may not) find useful:
du
/
dy
VD
Q VA
Re
E
p h
4 0 L
D
64
f
Re
hL f
53:071 Principles of Hydraulics & Hydrology
Exam 1 (Closed Conduit Flow)
Spring 2010
Name: _
Equations and constants you may (or may not) find useful:
du
/
dy
VD
Q VA
Re
E
p h
4 0 L
D
64
f
Re
hL f
53:071 Principles of Hydraulics & Hydrology
Exam 1 (Closed Conduit Flow)
Practice Exam
Name: _
Equations and constants you may (or may not) find useful:
du
=
= /
dy
VD
Q = VA
Re =
2
4 L
pV
h= z+ +
h
53:071 Principles of Hydraulics & Hydrology
Exam 1 (Closed Conduit Flow)
Practice Exam
Name: _
Equations and constants you may (or may not) find useful:
du
=
= /
dy
VD
Q = VA
Re =
2
4 L
pV
h= z+ +
h
53 2071 Principles of Hydraulics & Hydrology
Exam 2 (Open Channel Flow) N
Spring 2010 Name: @5?
Equations and constants you may (or may not) nd useJl:
V=C RSf RzA/P
53:071 Principles of Hydraulics & Hydrology
Exam 2 (Open Channel Flow)
Spring 2010
Name: _
Equations and constants you may (or may not) find useful:
V C RS f
R A/ P
0 RS f
Q VA
V
V
Q
1
AR 2 / 3 S 1 /
53:071 Principles of Hydraulics & Hydrology
Exam 2 (Open Channel Flow)
Practice Exam
Name: _
Equations and constants you may (or may not) find useful:
Q = VA
Re =
0 = RS f
R = A/ P
V (4 R)
8g
RS f
f
53:071 Principles of Hydraulics & Hydrology
Exam 2 (Open Channel Flow)
Practice Exam
Name: _
Equations and constants you may (or may not) find useful:
Q = VA
Re =
0 = RS f
R = A/ P
V (4 R)
8g
RS f
f
53:071 Principles of Hydraulics & Hydrology
Exam 3 (Engineering Hydrology)
Practice Exam
Name: _
Equations and constants you may (or may not) find useful:
x
F ( x) exp exp
6
0.5772
y ln( ln(1 p)
Lesson 4: Energy (Head) Losses Due to Pipe Friction
Darcy-Weisbach: Problems and Solution Procedures for Turbulent Flow
Find head loss (hf) given pipe size (D), type and discharge (Q):
k
1. Compute s
Lesson 5: Minor Losses and Grade Lines
Energy Grade Line (EGL) and Hydraulic Grade Line (HGL)
p
V2
1. A plot of the total (energy) head, z
, versus location in the pipe
2g
system is known as the ener
Lesson #5: Minor Losses and Grade Lines
Sudden Expansion
Entrance
Exit
1 of 4
Lesson #5: Minor Losses and Grade Lines
Fittings, Valves, Entrance/Exit Losses
2 of 4
Lesson #5: Minor Losses and Grade Li