MAE 2600 (SP13)
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TEST #2
This is a closed book exam. Show your work clearly and concisely!
Indicate answers and units. You have a full 50 min. period for the exam.
1. The 24-lb block has an unkno
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 17: Conservative Force. Work and Potential (15.3-15.4)
1. Basic concepts
Potential energy
dV F.dr
Principle of work and energy
1 2
1 2
mv1 V1 mv2 V2
2
2
Note: If a
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 18: Chapter 16.1, Principle of Impulse and Momentum
Basic Concepts
Newtons second law can be expressed as:
dv
F m dt
If we integrate with respect to time
t2
Fdt
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 16: Work Done by Particular Forces (15.2)
Note: for certain types of forces, we dont need to know the path to find the work.
1. Work done by particular forces
Weig
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 14: Chapters 13 and 14 Summary
Kinematics Review
r : position vector of P relative to origin O . Then:
dr
: velocity of P relative to O , and
v
dt
a
dv
: accelerat
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 19: Conservation of Linear Momentum, Impact
Basic Concepts
For a system of particles, if there is no external forces acting on the system, FAB FBA 0 ,
then, the to
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 15. Chapter 15 Work and Kinetic Energy
In this chapter we will show hoe Newtons second law, which is a vector equation, can be
transformed into a scalar equation.
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 13: Chapter 14 section (14.5)
Orbital Mechanics
Key concepts:
We can use Newtons second law expressed in
polar coordinates to determine the orbit of an
earth satel
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 12: Chapter 14 section (14.4)
Second Law Polar Coordinates
We can write Newtons second law as:
Fr er F e m(ar er a e )
where
d 2 r d
d 2r
2
ar 2 r
2 r
dt
dt
d
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 11: Chapter 14 section (14.3)
Normal and Tangential Components
Newtons second law can be written in terms of tangential and normal components:
Ft et Fnen m(at et
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 20: Oblique Central Impacts
The objects approach each other at an oblique
angle.
Incase, the forces that they exert on each other
during their impact are parallel
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 21: Angular Momentum
Basic Concepts
Principle of Angular Impulse and Momentum
r F r ma r m
rF
dv
dt
dH O
dt
(1)
(2)
where the vector
HO r mv
(3)
is called the ang
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 24: 17.4: Instantaneous Centers
Objective:
Learn the concept of Instantaneous center
Learn on how to find the Instantaneous center
Apply the concept of Instantaneo
MAE 2600 (SP13)
TEST #I
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This is a closed book exam. Show your work clearly and concisely!
Indicate answers and units. You have a full 50 min. period for the exam.
1. At the instant shown, cars A and B are trav
MAE 2600 (SP13)
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TEST #3
Name:
This is a closed book exam. Show your work clearly and concisely!
Indicate answers and units. You have a full 50 min. period for the exam.
1. Due to an increase in power, the motor rotates pulley
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 28: Summary - Planar Motion of Rigid Bodies
Relative Velocities
rA rB rA / B
v A v B v A/ B
Velocity Formulae
v A v B v A/ B
v A / B rA / B
The instantaneous cente
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 26: (17.6) Sliding Contact
Objective:
Study the motion of rigid bodies when relative motion involved
Introduce the concept of the body-fixed reference frame
Exampl
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 29, (Chapter 18.1-18.2): Planar Dynamics of Rigid Bodies
Preview of Equation of Motion
The equations governing the planar motion of a rigid body are Newtons second
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 27: (17.7) Moving Reference Frames
Motion of a Point Relative to a Moving Reference Frame
v A v B v Arel rA / B
a A a B a Arel 2 v Arel rA / B rA / B
1
057010 Dyn
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 22: Chapter 17.1-17.2
Planar Kinematics of Rigid Bodies
Objective:
To analyze the motion of objects, including their rotational motions
1. A quick overview of rigi
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 25: (17.5) General Motion: Accelerations
Objective:
To analyze the accelerations of rigid bodies
Key equations
a A aB a A/ B
a A / B r A / B ( r A / B )
Planar mot
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 23: 17.3 General Motion: Velocities
Objective:
To analyze motions that combine translation and rotation
Cross product a quick review
Relative Velocities
rA rB rA /
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 10: Chapter 14 section (14.1-14.2)
Chapter objectives:
In this chapter, we relate cause and effect using Newtons second law of motion.
By drawing the free-body dia
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 9: Kinematics Review: More Problems
r : position vector of P relative to origin O . Then:
dr
: velocity of P relative to O , and
v
dt
a
dv
: acceleration of P rela
057010 Dynamics
Instructor: S. Rahmatalla
College of Engineering
University of Iowa
Lecture 8: Section 13.8
Relative Motion
Objective:
Introduce the concepts relative motion
The position of A relative to B is:
rA rB rA / B
(1)
The derivative of equation (
Dynamics, Fall 2015 Examl Name:
1. (35 pts) The 60—kg skateboarder coasts down the
circular track of radius 4 m. If he starts from rest when
0 = 0°, determine the magnitude of the normal reaction
the track exerts on him when 6 = 60°.
. 0 2
N=m3 Sl
Comparing Eqns 5 and 6, we see that the post impact velocity is the same in both scenarios
Note: This result has an important implication in the real world. For example, you want to study the damage due to a head-on collision
between two similar model veh
Name: _
Univ ID#: _
Dynamics 57:010 - Spring 2002
Instructor: M.L. Raghavan
Sample Test 2
Duration: 50 minutes
Total points: 60; Open Book, Notes, Calculators
Answer any 3. Each question carries 20 points
1. The mass m=1Kg, the spring constant k=200 N/m a
Dynamics 57:010 - Spring 2002
Instructor: M.L. Raghavan
Sample Test 2
Duration: 50 minutes
Total points: 60; Open Book, Notes, Calculators
Answer any 3. Each question carries 20 points
1. The mass m=1Kg, the spring constant k=200 N/m and the unstretched l