Engineering Mechanics 324
Mechanics of Materials
28 September 2016
Statically Indeterminate Torsion
&
Finite Element Analysis
EM 324 / Topic 13
2016 Iowa State University; all rights reserved. Posting on websites available to non-ISU students is prohibit

W0
180 mm
20 mm
180 mm
20 mm
2. Given a simply-supported beam with the cross-section shown, L = 3m, and w0 = 100 kN/m, draw shear and moment diagrams, and
calculate the normal stress at the top and the bottom of the beam at cuts AA, BB, CC, DD, and EE; an

Average compressive stress (psi)
Average tensile stress (psi)
0
200
150
100
50
-1000
-2000
-3000
-4000
-5000
(in/in)
1. A retaining wall is constructed of concrete pillars with the cross-section shown. The pressure of the earth on the backside of the wall

ME 332 Assignment VII
Due: Monday, October 19, 2015, at 2:00 PM on BlackBoard
VII-1. In a vapor-compression refrigeration cycle, Refrigerant 134a exits the evaporator at
10oC, 1.4 bar. The refrigerant enters the condenser at 12 bar, 70oC, and exits at 38

ME 332 Assignment VIII F15
Due: Monday, November 2, 2 PM on BlackBoard
VIII-1. An ideal gas mixture contains 0.3 kg of CO2, 0.5 kg of O2, and 0.5 kg of CO at 25oC, 2
bar. For the mixture, determine
(a) the analysis in terms of mass fractions.
(b) the appa

FINAL EXAM
Summer 2013 Name:
Show all of your work and circle your section number. Final answer must be shown in
the space provided below.
1 XE
M
1. (25 Points) A rope is attached to the top corner of a 450-N block, passes over a
ﬁxed drum, and is a

EXAM 3
Summer 2013 Name:
Show all of your work and circle your section number. Final answer must be shown in
the space provided below.
1 XE
W
1. (25 Points) A cord is
wrapped around a frictionless
pulley and supports a 40—1b
weight. The vertical surface

Stresses, Strains, and Deformations
Stress transformation:
0
Normal stress due to axial loading: =
Normal strain due to axial loading: =
= cos 2 + sin2 + 2 sin cos
Normal strain due to thermal effects: =
Elongation: = 0 = 0 =
Poissons ratio: =
Nor

Math 267 A Fall 2013 Exam 3
Justify your answers by showing all work
1 Write the followin s stem of 2nd order equations as a 1st order
g 3
system in the form 5’ 2 AE, with :3 a (4 X 1) column vector and A
a (4 x 4) matrix.
,0 a:”—l—3m+2y:0, y"—2:r:0.
(2)

50 MPa
10 MPa
E = 70 GPa
= 0.25
3. The stress distribution shown on the square cross-section
of an aluminum beam is a result of combined axial loading and
flexural loading. (a) Calculate the normal strain values at the
top edge and at the bottom edge of

Supplemental Homework Assignment #3
EM324 Mechanics of Materials Spring 2016
Last name
First name
DUE in-class on February 29
A uniformly distributed vertical load acts over a horizontal portion of
beam ABC as shown below. The beam is supported by a frict

Engineering Mechanics 324
Mechanics of Materials
14 & 21 October 2016
Deflection of Beams by Superposition
Including Indeterminate Beams
EM 324 / Topics 20 & 21
2016 Iowa State University; all rights reserved. Posting on websites available to non-ISU stu

Engineering Mechanics 324
Mechanics of Materials
2 September 2016
Non-Destructive Testing (NDT) and Fatigue
EM 324 / Topic 6
2016 Iowa State University; all rights reserved. Posting on websites available to non-ISU students is prohibited.
1
Metal Fatigue

Engineering Mechanics 324
Mechanics of Materials
4 November 2016
The Principles of Principal Stresses
EM 324 / Topics 27
2016 Iowa State University; all rights reserved. Posting on websites available to non-ISU students is prohibited.
1
Theory unites wit

Engineering Mechanics 324
Mechanics of Materials
22 August 2016
Introduction;
Internal Forces and Moments
EM 324 / Topic 01
Iowa State University
1
This Course
Some students find EM 324 difficulteven if Statics was easy
1) No mental framework (schema) to

EXAM ID#
EXAM 3
SPRING 2016
Mechanics of Materials
NAME:
Equation Sheet
FF
Stresses, Strains, and Deformations
Normal stress due to axial loading: =
Direct Average shear stress: =
Stress Transformation & Principal Stresses:
=
Total normal strain: =
Angle

EXAM ID#
EXAM 1
SPRING 2016
Mechanics of Materials
NAME:
Equation Sheet
FF
Units and Conversion Factors
Stresses, Strains, and Deformations
Normal stress due to axial loading: =
=
Average shear stress: =
Hookes Law: =
Poissons ratio: =
Shear strain: =
2

Supplemental Homework Assignment #4
EM324 Mechanics of Materials Spring 2016
Last name
First name
DUE in-class on March 28
Exam ID
The uniform dimension pipe shown transports fluid and has internal pressure p. In addition to internal
pressure, the pipe su

Supplemental Homework Assignment #2
EM324 Mechanics of Materials Spring 2016
Last name
First name
DUE in-class on February 22
Exam ID
A shaft and gear assembly shown in the illustration below. Both shafts ABC and DE are solid. Refer to the
tables on the n

EXAM ID#
EM 324
EXAM 4
Mechanics of Materials
Spring 2016
NAME:
Equation Sheet
FF
=
Normal stress due to axial loading:
Hookes Law for uniaxial stress: =
Poissons ratio:
Theories of Failure
Maximum shear stress: . <
Maximum distortion energy
(for plane s