Homework 1, due January 15, 1999
Problem 1. Ashcroft—Mermin 4.1
For all three parts it is clear that the points on the corners of the original
simple cubic lattice have the same environment. We need to compare the corner
points with the new points.
PHYS 635 Solid State Physics Take home exam 1
Gregory Eremeev Fall 2004 Submitted: November 8, 2004
Problem 1:Ashcroft & Mermin, Ch.10, p.189, prob.2 a) Lets prove xx = yy = zz = xx = = Now 0 = xx yy = dr (x2 y 2 ) |(r)|2 U (r) (3) dr (r) x (r) U (r) = x
PHYS 635 Condensed Matter Physics
Assignment 4 (Nov 9, 2004) Solutions
1. A&M Problem 12.2. For electrons near a band minimum or maximum, we have
(1.1) 2 where M1 is the reciprocal eective mass tensor. As can be seen from its denition in Eq. (12.29) in
C:~+H~ 'P T c
?-~ (A.h 0 f)
I UK I
Homework 4, due February 22, 1999
Problem 1. AshcroftMermin 12.2
(a) We have
so?) = @7212? - M-l - I?
where we have taken the minimum energy to be zero and the minimum at
the origin. This does not change the results.
The area A(e, k2) is the area inside t