Solution Quiz 1 chapter 20
Q.1. If one bag contains a charge 8Q and another one contains charge Q, the 8Q-bag exerts 8 times as much force on the Q-bag as the Q-bag exerts on the 8Q-bag. A) True B) False Q.2. A plastic rod is charged
Phys 299 Your Name: _ Your List# _ May 24, 2010 Chapter 21 Test# QUIZ 2 Due : Wed May 26 in class. Submit your written work on the back of this sheet only. Mark Scantron in class.
Q.1. Q.2. Q.3. Q.4. If more electric field lines point into a balloon than
THE MAGNETIC FIELD
ActivPhysics can help with these problems: Activities 13.4, 13.6, 13.7, 13.8 Section 29-2: Problem
1. (a) What is the minimum magnetic field needed to exert a 5.4 10 15-N force on an electron moving at 2.1 10 7 m/s ? (
ActivPhysics can help with these problems: Section 12, "DC Circuits" Section 28-1: Problem
1. Sketch a circuit diagram for a circuit that includes a resistor R1 connected to the positive terminal of a battery, a pair of
INTERFERENCE AND DIFFRACTION
ActivPhysics can help with these problems: Activities in Section 16, Physical Optics Section 37-2: Problem
1. A double-slit system is used to measure the wavelength of light. The system has slit spacing d 15
ActivPhysics can help with these problems: Activities 13.9, 13.10 Sections 31-2 and 31-3: Problem
1. Show that the volt is the correct SI unit for the rate of change of magnetic flux, making Faraday's law dimens
Section 27-1: Problem
A wire carries 1.5 A. How many electrons pass through the wire in each second?
The current is the amount of charge passing a given point in the wire, per unit time, so
pg Phys 299 Chapter 20 Practice Pr soln: #15, 16, 17, 22, 25, 27, 29,31, 35,38, 59, 60, 61,67 15:
DEVELOPSince the magnitude of elementary charge e is e = 1.6 1019 C, the number of electrons involved is given by Q/e.
EVALUATESubstituting the values give
Chapter 22 Practice Pr solns:
W = qV = (50 C)(12 V) = 600 J.
The potential difference and the work per unit charge, done by an external agent, are equal in magnitude, so
(Note: Since only magnitudes are needed in this problem, we omitted the subscript
Chapter 24 Practice Pr soln:
INTERPRETThis problem is about applying Ohm's law to find the resistivity of a rod. DEVELOPIf the rod has a uniform current density and obeys Ohm's law (Equations 24.4a and 4b), then its resistivity is
E E E ( d 2 /
Phys 299 2010 Quiz 3 Chapter 22
Q.1 As an electron moves from a high potential to a low potential, its electrical potential energy A) increases. Q.2. In the figure, charge is placed on the piece of copper. How will the charge be distributed on th
Chapter 23 Practice problem solutions # 19, 20,21,26,30,34,40,44,48,52,54
19. (a) We find the electric field to be E=
(b) The potential difference is
q (1.1 C) = = 1.99 MV/m 12 2 0 A (8.85 10 C /N m 2 )(0.25 m) 2 V = Ed = (1.99 MV/m)(5 mm) = 9.94 kV
Physics 299 Important Constants and Equations
Note: Some basic simple equations you are supposed to know. Here we are providing you with only some important equations that were introduced in the chapters given below.
4. 5. 6. 7. 8.
g = 9.80 m/s
Phys 299 Your Name: _SOLUTIONS_ Your List# _ May 23, 2010 QUIZ 2 Due : Wed May 26 in class. Submit your written work on the back of this sheet only. Mark Scantron in class.
Q.1. Q.2. Q.3. Q.4. If more electric field lines point into a balloon than come ou
Phys 299 May 27, 2010 Practice Quiz on Chapter 22 There is one correct answer choice per question. Answers will be posted Saturday evening.
Q.1 As an electron moves from a high potential to a low potential, its electrical potential energy A) increases. B)
PHYS 299- 75
HOLLY MCTAGGART (5011655)
1) Two particles each have a mass of 6.00 g. One has a charge of +1.5 C and
the other has a charge of 1.5 C. They are initially held at rest at a distance of
0.80 m apart. Both are then released and accel
PHYS 299- 75
HOLLY MCTAGGART (5011655)
1. What is the magnitude and direction of the net gravitational force exerted on particle 1 by the
other two particles?
2) What is the magnitude and direction of the gravitational eld at point P shown
Practice Pr solns: # 22,25,27,29, 30 ,31, 35, 36, 41, 47, 48, 59
When the surface is perpendicular to the field, its normal is either parallel or anti-parallel to E.
2 2 Then Equation 21.1 gives = E A = EA cos(0 or 180) = (850 N/C)(2 m