Week 3 Assignment
1. A 5600 kg mass car is taking a turn at 72 m/s. If the frictional force here is 44,000N,
what is the radius of curvature of the turn?
F=
mv
r
2
2
m v 2 5600( 72 )
r=
=
=659.78 m
F
Week-1 assignment;
Introduction, Measurement, Estimating
1.
One lightyear is defined to be the distance light can travel in one year.
o
What is this distance in meters?
1 light year = 365 days * 86400
1. A ship has a top speed of 3.0 m/s in calm water. The current of the ocean tends to push the boat at 2.0 m/s
on a bearing of due South. What will be the net velocity of the ship if the captain point
1.
A ship has a top speed of 3.0 m/s in calm water. The current of the ocean tends to push the boat at 2.0 m/s
on a bearing of due South. What will be the net velocity of the ship if the captain point
1. One lightyear is defined to be the distance light can travel in one year.
o
What is this distance in meters?
9.461x1015m=9,461,000,000,000,000m
o
How long does it take for light to get to the Moon
1. A 5600 kg mass car is taking a turn at 72 m/s. If the frictional force here is 44,000N, what is the
radius of curvature of the turn?
659.78m
2. Up where the ISS (International Space Station) orbits
5.1 THE NATURE OF THERMODYNAMICS Thermodynamics is concerned with the relationship between the energy changes that occur in chemical and physical processes. In effect, the laws of thermodynamics are t
Lab 4
Data Tables & Short Answers:
Fill in the charts below:
Ball Position
PE
KE
TE or E
A
0.60 J
0.00 J
0.60 J
B
0.05 J
0.55 J
0.60 J
C
0.25 J
0.35 J
0.60 J
D
0.40 J
0.20 J
0.60 J
E
0.16 J
0.44 J
0.6
Lab 6
t = .025
m = .001kg
M = .050kg
h = y = - .984 (- .789) = .195m
PE = total *g* y = .051kg * 9.81m/s2 * .195m = .098 J
KE B/b = PE B/b
(m+M)V2 = (m+M) g* y
V (block and bullet) = (2*g*PE)
2*9.81*
Lab 2
Excel Data Table: (To be supplied by student)
= 90 degrees
R (at v0 = 10 m/s & g = 10m/s2) = 10 meters
Graph of R (y-axis) vs. :
Range (m) vs Angle (degrees)
12
10
8
Range (m)
6
4
2
0
0
10
20
3
Lab 5
I weigh 220 lbs = 100kg (I actually weigh 220 and it says it
on my drivers license)
Weightyou= 100kg
Workyou = J
Time = 5 sec
11 steps
7 inches each converts to 17.78cm
H = 17.78*11 = 195.58cm
P
Lab 5
Weightyou=
107 Kg
Workyou =
10447 J
Poweryou =
950 Wat
Poweryou(in kW) =
.9497 kWh
Money that this climb is worth =
Money that climbing for an hour is worth =
$0.0002
$0.86
235lbs
Work = mgh, 10
William Torr
G00140322
WK 3 Circular Motion Assignment
#1. A 5600 kg mass car is taking a turn at 72 m/s. If the
frictional force here is 44,000N, what is the radius of curvature of
the turn? (10 poin
William Torr
PH 220 WK2
G00140322
#1. A ship has a top speed of 3 m/s in calm water. The current of
the ocean tends to push the boat at 2 m/s on a bearing of due
South. What will be the net velocity o
William Torr
G00140322
PH 220
WK 4
#1. A rail car of mass 4500 kg is moving with a velocity of 12.4
m/s collides with a stationary rail car of mass 6700 kg. What is
the velocity of the two cars
wk 5 assignment, G00140322 1
Torr, William J.
G00140322
Ph220
11/07/2017
#1. A street light is supported by two wires and each makes
a different angle from each other. The one on the left is 32
degr
Name
Gaskins,Christina
Grantham
School _ Date
20171029
Velocity: A Bats Eye View of Velocity
PURPOSE
There are a number of useful ways of modeling (representing) motion. Graphing position, velocity, a