Week-1 assignment;
Introduction, Measurement, Estimating
1.
One lightyear is defined to be the distance light can travel in one year.
o
What is this distance in meters?
1 light year = 365 days * 86400 seconds * 3 x 10 8 meters /second
1 light year = 94607
PH220
Week 2 Assignment
Grantham University
Week-2 assignment;
Kinematics in Two Dimensions; Vectors and Dynamics: Newton's Laws of Motion
1. A ship has a top speed of 3.0 m/s in calm water. The current of the ocean tends to push
the boat at 2.0 m/s on a
Week-2 assignment;
Kinematics in Two Dimensions; Vectors and Dynamics:
Newton's Laws of Motion
1. A ship has a top speed of 3.0 m/s in calm water. The current of the ocean tends to push
the boat at 2.0 m/s on a bearing of due South. What will be the net v
PH220
Week 1 Assignment
Grantham University
Week-1 assignment;
Introduction, Measurement, Estimating
1. One lightyear is defined to be the distance light can travel in one year.
o
What is this distance in meters?
1 light year = 365 days * 86400 seconds *
Lab 6
t = 0.761 seconds
h = y = 0.195 m
v(bullet-calculated) = 99.7 m/s
Initial height = -0.984 m
Maximum height = - 0.789
so height achieved = -0.789 (-0.984) = 0.195 m
Velocity of bullet can be calculated by formula
v=
m+M
m
2 gh =
0.001 + 0.050
2 * 9.8
v0 = 10 m/s
g = 10 m/s^2
Thisinvolvesaprojectilebeingfiredupwardatanangletothehorizontal.YouaretoprogramthespreadsheetExceltodeterminethemaximuminjectionanglethatwillresultinthegreatestdownrangedistance,R.Assumevo=10m/sandgisapproximatedasg=10m/s^2.Fillin
Week-3 assignment;
Circular Motion, Gravitation, and Work and Energy
1. A 5600 kg mass car is taking a turn at 72 m/s. If the frictional force here is 44,000N,
what is the radius of curvature of the turn?
So the radius of curvature must be 659.78m
2. Up w
M2 Discussion Forum: Newton's Laws of Motion
A space explorer moving through space in the middle of intergalactic space, very far from
any planet or star. He notices a large rock floating around the cabin of the ship.
The explorer wishes to take it as a s
Lab 1 Motion
Lab 1 (See textbook pages 36-39, Chapter 2, Lesson 2) involves the graphical analysis of
velocity. This simulation can be downloaded from Granthams Website under PH220.
Simulations; its file name is EXP #1 C1 IP.ip. Fill in the data table, an
PH220
Week 3 Assignment
Grantham University
Week-3 assignment;
Circular Motion, Gravitation, and Work and Energy
1. A 5600 kg mass car is taking a turn at 72 m/s. If the frictional force here is 44,000N,
what is the radius of curvature of the turn?
So the
Linear Momentum and Rotational Motion
1.
A rail car of mass 4500 kg is moving with a velocity of 12.4 m/s collides with a stationary rail car of mass
6700 kg. What is the velocity of the two cars if they stick after they collide?
2.
A tennis player hits a
1.A 10.0 cm radius piston compresses a gas isothermally from a height of 15.
0 cm to 2.50 cm at a constant pressure of 2.0 atm.
W = PdV = 2*(3.14* 0.1^2 * 0.15 - 3.14*0.1* 0.025)
W =331.25 J
dQ = dU + dW = 331.25 J
2.Sketch a PV diagram for the following
1.A diamond has a mass of 56.6 g and the gold ring it is set in has a mass of
125.6 g. How many carbon atoms are there compared to gold atoms?
number of carbon atoms=6*10^23*56.6/12
=2.83*10^24 atoms
number of gold atoms=6*10^23*125.6/197
=3.825*10^23 ato
1.A spring with negligible mass stretches 34.0 cm when a 144 g gram mass i
s suspended from it. Now I suspend a mass m from the spring. If it oscillates
at an angular frequency of 4.51 rad/s, what is the mass?
kx = mg
k = .144*9.81/.34
w = sqrt(k/m)
4.51^
PH220
Week 8 Assignment
Grantham University
Week-8 Assignment
The Law of Thermodynamics
1. A10.0cmradiuspistoncompressesagasisothermallyfromaheightof15.0cmto2.50cm
ataconstantpressureof2.0atm.
W=PdV=2*(3.14*0.1^2*0.153.14*0.1*0.025)
W=331.25J
dQ=dU+dW=331
Chap. 1, #1.
The age of the universe is thought to be about 14 billion years. Assuming two significant figures,
write this in powers of ten in (a) years, (b) seconds.
(a) 1.4 10 Years
10
(b) 4.4 17 seconds
10
Chap. 1, #9.
Multiply 2.079 2 m by 0.082 1 , t
M3 Discussion Forum: Gravitational Force
The gravitational force on the Moon due to the earth is only about one half the force on the
Moon due to the sun. Why isnt the Moon pulled away from the Earth?
It is correct that sun exert more force on moon than e
Lab 5
Weightyou= 60 kg
Workyou = 5880 J
Poweryou = 490 watt
Poweryou(in kW) = 0.49 kW
Money that this climb is worth = 0.013064 cents
Taking my weight as 60 kg and height climbed = 10 m
Work = mgh = 60*9.8*10 = 5880 J
Power = work /time
If time taken obta
Lab 1 Motion
Lab 1 (See textbook pages 36-39, Chapter 2, Lesson 2) involves the graphical analysis of
velocity. This simulation can be downloaded from Granthams Website under PH220.
Simulations; its file name is EXP #1 C1 IP.ip. Fill in the data table, an
Lab Project Answer Sheet
Name: _
E-mail address: _
Lab 2
Excel Data Table: (To be supplied by student)
= _
R (at v0 = 10 m/s & g = 10m/s2) = _
Graph of R (y-axis) vs. : (To be supplied by student)
Student # _
Lab 3
T (at t = 2.54 s) = _
FN = _
Lab 4
Data