Lab 6
t = 0.761 seconds
h = y = 0.195 m
v(bullet-calculated) = 99.7 m/s
Initial height = -0.984 m
Maximum height = - 0.789
so height achieved = -0.789 (-0.984) = 0.195 m
Velocity of bullet can be calculated by formula
v=
mM
m
2 gh
0.001 0.050
2 * 9.8 * 0
Lab 5
Weightyou= 60 kg
Workyou = 5880 J
Poweryou = 490 watt
Poweryou(in kW) = 0.49 kW
Money that this climb is worth = 0.013064 cents
Taking my weight as 60 kg and height climbed = 10 m
Work = mgh = 60*9.8*10 = 5880 J
Power = work /time
If time taken obta
PH220
Wk 8 Assignment
The Law of Thermodynamics
1. A 10.0 cm radius piston compresses a gas isothermally from a height of 15.0 cm to 2.50 cm at a
constant pressure of 2.0 atm.
W = PdV = 2*(3.14* 0.1^2 * 0.15 - 3.14*0.1* 0.025)
W =331.25 J
dQ = dU + dW = 3
WK4 PH220
Lab 4
Data Tables & Short Answers:
Fill in the charts below:
Ball Position
-3.66,3.02
-.77,.27
.69,1.37
1.93,2.02
3.57,.80
3.77,2.97
PE
.60J
.05J
.27J
0.4J
.16J
0.59J
KE
0J
.55J
.33J
0.2J
.44J
.01J
TE or E
.60J
.60J
.60J
.60J
.60J
.60J
Is total
PH220WK6
Week-6 Assignment
Vibrations, Waves, and Sound
1. A spring with negligible mass stretches 34.0 cm when a 144 g gram mass is suspended from it. Now
I suspend a mass m from the spring. If it oscillates at an angular frequency of 4.51 rad/s, what is
PH220wk4
Linear Momentum and Rotational Motion
1. A rail car of mass 4500 kg is moving with a velocity of 12.4 m/s collides with a
stationary rail car of mass 6700 kg. What is the velocity of the two cars if they
stick after they collide?
m1*v1 = (m1 + m2
Lab 5
Weightyou=
107 Kg
Workyou =
10447 J
Poweryou =
950 Wat
Poweryou(in kW) =
.9497 kWh
Money that this climb is worth =
Money that climbing for an hour is worth =
$0.0002
$0.86
235lbs
Work = mgh, 107*9.8*10
Power = work/time (11 Seconds)
kW = Power/1000
W5 Assignment "Static Equilibrium and Fluids"
David England
Grantham University
1. A street light is supported by two vertical wires and each makes a different angle from each other.
The one on the left is 32 degrees and the one on the right is 43 degrees
W7 Assignment "Temperature, Kinetic Theory, and Sound"
David England
Grantham University
1. A diamond has a mass of 56.6 g and the gold ring it is set in has a mass of 125.6 g. How many carbon
atoms are there compared to gold atoms?
a. carbon atoms=6*1023
Lab 4
Data Tables & Short Answers:
Fill in the charts below:
Ball Position
A
B
C
D
E
F
PE
0.60
0.05
0.25
0.40
0.16
0.60
KE
0.00
0.55
0.35
0.20
0.44
0.01
TE or E
0.60
0.60
0.60
0.60
0.60
0.60
Is total energy (T.E.) conserved in every case (within experimen
W2 Assignment "Kinematics in Two Dimensions; Vectors and Dynamics: Newton's Laws of Motion"
David England
Grantham University
1. A ship has a top speed of 3.0 m/s in calm water. The current of the ocean tends to push the boat at
2.0 m/s on a bearing of du
W8 Assignment "The Laws of Thermodynamics"
David England
Grantham University
1. A 10.0 cm radius piston compresses a gas isothermally from a height of 15.0 cm to 2.50 cm at a
constant pressure of 2.0 atm.
a) How much heat was added to the gas?
i. W= PV =
1. One lightyear is defined to be the distance light can travel in one year.
a) What is this distance in meters?
i. Light travels at 300000km/sec or 186,000mps
ii. 300,000*1000 = 300,000,000
iii. 60sec*60 min=3600 sec/hr
iv. 3600*24hrs = 86400 secs/day
v.
Week 3 "Circular Motion; Gravitation; Work and Energy"
David England
Grantham University
1.
A 5600 kg mass car is taking a turn at 72 m/s. If the frictional force here is 44,000N, what is the radius of
curvature of the turn?
mv 2
r
a.
F=
b.
m v 2 5600( 72
Week 4 Assignment "Linear Momentum and Rotational Motion"
David England
Grantham University
1. A rail car of mass 4500 kg is moving with a velocity of 12.4 m/s collides with a stationary rail car
of mass 6700 kg. What is the velocity of the two cars if th
1. A spring with negligible mass stretches 34.0 cm when a 144 g gram mass is suspended from it.
Now I suspend a mass m from the spring. If it oscillates at an angular frequency of 4.51 rad/s,
what is the mass?
a) Kx = mg so k= .144 * 9.8/.34
b) W=
k
m
c)
Lab #7
Jeremy Davis
G00124462
Department of Physics
PH220
Professor Mark Cappuzzo
Jeremy Davis
G00124462
Professor Cappuzzo
Lab 7
red
blue
A = _0.010- (-6.588)= 6.578m_
A = _2.527-0.003= 2.524m
T = _7.240 s_
T = _4.480s_
f = _1/7.240 s= 0.138 hz_
f = 1/4.
Lab #6
Jeremy Davis
G00124462
Department of Physics
PH220
Professor Mark Cappuzzo
Jeremy Davis
G00124462
Professor Cappuzzo
Lab 6
t = _0.793 s_
yf-yi= -0.789 - (-0.984) = 0.195 m
h = y = _0.195 m_
v(bullet-calculated) = _0.246 m/s_ 0.195/0.793 = 0.246 m/s