Week 5 Series and Parallel Inductive Reactance
Consider the series inductive reactive circuit:
Calculate the following: (Express all answers in magnitude/phase angle form)
a.
Zeq
Z eq = R1 + R2 + X L1 + X L2
X= jL
X 1 = j L1 = j [ 2 1000 80 103 ] =j502.4
Name:
GID:
Lab 5: Week 5 Inductive Reactance and Inductive Circuits
Grantham University
Date:
Introduction:
In week 5 lab we are going to perform a series of calculations and simulations. The simulations
will be shown in the circuit design section of this
Name:
GID:
Lab 6: Week 6 RC and L/R Time Constants
Introduction:
In week 6 lab we are going to perform a series of calculations and simulations in series L/R and
RC circuits. The simulations will be shown in the circuit design section of this report. The
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VS = 120 /(10/1) = 12V
12/.707 = 17Vdc
Subtract voltage drop across diodes
17 1.7 = 15.6Vdc
15.6Vdc across the capacitor
Current through 390 ohms resistor =
15.6/390 = 40mA
Current through RS =
Vz = 6V
Rs = 270ohms
6/270 = 22mA
Capacitor supplies the sum
IB = 10V-.7v/ 330 kOhms = 28.2uA
VCE = 7.76V
V = 10V = 7.76/ 470ohms = 16.5mA
Bdc = 16.5mA/ 28.2 uA = 579 Gain
I found that the current gain that was measured to be significantly higher then the 100- 300 found
in the the data sheet. If I used the current
VE = 5v - .7v = 4.3v
IE = 4.3/1.5kohms = 2.9mA
ICRC = (2.9mA)(4kohms) = 3.8V
VCE = 4.3v 3.4V = .9V
There is somewhat of a discrepancy between the measured values and the theoretical values.
This is somewhat due to the difference between potential transist
3-20 There would be zero Forward volts. It would most likely short the diode from excessive
current, since you would be going from 100k ohms to zero ohms.
3-21 The resistor or the diode shorted
3-22 The diode could be open, a wire between the components a
Transformers
1.
o
Watch the videos
Week 4 Video Lecture Multisim Transformers
Consider the circuit demonstrated in this weeks presentations. With the
turns ratio modified to 20:1, calculate the following values of Vs and Is for the given
values of RL in t
Fundamental Properties of AC Circuits/Lab
Midterm
Show work for full credit. Include MultiSIM screenshots where indicated.
1.
1.
2.
For the circuit below, solve for the following:
RT = R1+R2+R3= 2kOhms + 1kOhms + 6kOhms = 9kOhms
IT (pk), IT (p-p), IT (rms
CHAPTER 1
113. Fill in all of the empty cells in Table P113 by performing the indicated conversion as shown in the
row labeled sample.
114. Fill in all of the empty cells in Table P114 by performing the indicated conversion as shown in the
row labeled sam
Inductance
1.
Calculate the inductance of a coil that induces 120V when the current through it
changes at a rate of 5A/s.
L = VL/di/dt = 120V/5A/s = 24 H
2.
Calculate the inductance of a coil that induces 850V when the current through it
changes at a rate
Capacitive Reactance
Watch the videos
Week 2 Video Lecture - Capacitive Reactance
Consider the circuit below:
figure 1
For each value of the frequency in the chart below, perform calculations for Ic, Vc and Xc.
Freque
Calculated Ic
ncy
Calculated Vc
XC (F