WOOD
Basic and Fundamental Wood Properties and Design Considerations
E. Raymond DesOrmeaux PE, F. ASCE
1
WOOD
Why Wood? Commonly used Ordinarily plentiful Good strength compression & tension Works easy cutting & fastening
Some Limitations
Fire protection
CIVE 335 Stress Formula Lecture 1. f = P / A f = force per unit area
a. Used to determine STRESS b. Used for Analysis
2. P = f A
a. Used to determine Load Capacity of a member
3. A = P / f
a. Used to determine the required Area for a required Load b. Used
CIVE 335
Quiz # 2
9/9/08
ANSWER DOCUMENT
Name (Last, First)
Total Score =
SHOW ALL CALCULATIONS. A RESULT ONLY IS NOT ACCEPTABLE. 1 A concrete pile has dimensions of 24" square, and a length of 27'. How many cu.yds. is this?
24" = 2' 2' x 2' = 4 sq.ft.
10
CIVE 335
Problem Solving Due:
8/28
ANSWER DOCUMENT
Total Score
=
SHOW ALL CALCULATIONS AND DIMENSIONS. A RESULT ONLY IS NOT ACCEPTABLE. 1 Compute the concrete volume in cu.yds. of a slab-on-grade with dimensions of 200' x 80' x 7"
7" = 7/12 = 0.583'
200'
CIVE 335
Part Area (in2)
Centroids
y (in) A x y (in3)
HW # 1
Example - p. 599 Table A.1 for Figure A.2 at top of page
Name:
A.1 - d
ANSWER DOCUMENT
Area (in2) y (in) A x y (in3)
Due Date:
8/28/08
Part
1 2 3 4
20.000 60.000
11.000 5.000
220.000 300.000 0.0
Name (Last, First) Instructor: E. R. DesOrmeaux, P.E.
100
Total
Exam # 3
CIVE 335
Exam # 3
Part 1 & II
Tuesday, November 25, 2008
Page 4 Part II
25
Page 3 Part II
25
Page 2 Part 2
20
Page 1 Part II
15
Part 1
15
Part 1 Part II
True & False Problems
15 Minu
Name (Last, First) Instructor: E. R. DesOrmeaux, P.E.
Exam # 2 Total
CIVE 335
Exam # 2
Thursday, November 06, 2008
Instructions: 1 Please do not open the document or start the Exam until directed by the Instructor. 2 Problems requiring mathematical soluti
Basic Structural CIVE 335
A review of basic Structural Engineering
(U.S. units are used)
The material in this presentation covers a significant portion of Chapter 2 in the textbook. Forces Stress & Strain Hooke's Law & Elastic Limit Modulus of Elasticity
CIVE 335
3.8.A
Date
10/30/08
Assignment #
16
Problem 3.8 - A p. 103
NAME (Last, First)
Compute the critical shear stress and plot the distribution of shear stress on the cross section. 8" 3" 2" fv V Q = shear stress = shear force at the beam section = mom
CIVE 335
3.6.A
Due Date
10/28/2008
Assignment #
15
Problem 3.6 A p. 95
NAME (Last, First)
Find the value for the maximum bending moment in the beam. 4 kips 4 kips Fy = 0 8' 8' 8' Fy = R1 + R2 R2 (R2 x 24') - (4 kips (R2 x 24') = 96 kip-ft R2 = 96 kip-ft /
CIVE 335
3.5.E
Date
10/23/08
Assignment #
14
Problem 3.5. E p. 91
NAME (Last, First)
Draw the shear and bending moment diagrams for the beams, indicating all critical values for the diagram.
500 lb 4'
600 lb 3'
400 lb Fy = 0 5' Ro Mo Fy = Ro Ro = 1,500 lb
CIVE 335
3.5.A 500 lb 4'
Date
39737
Assignment #
12
Problem 3.5. A p. 87
NAME (Last, First)
Draw the shear and bending moment diagrams for the beams, indicating all critical values for the diagram. 1,200 lb 3' R1 7' 800 lb 5' R2 (R2 (R2 (R2 R2 x x x = Fy
CIVE 335
3.4.A
Date
10/9/08
Assignment #
10
Problem 3.4. A
p. 83
NAME (Last, First)
Draw the shear and bending moment diagrams and note all critical values for shear and moment.
16,000 lb Fy = 0 Fy R1 M R1 = 0 (R2 x 16') - (16,000 lb (R2 x 16') = 96,000 f
CIVE 335
Problem 2.1 A.
Due Date
9/11/08
Assignment #
5
Chapter 2 Problems 2.1 A - H
NAME (Last, First)
Find the cross-sectional area of the bar in tension f = P/ A A=P/f A = 40 kips / 12 ksi
P = 40 kips
f = 12 ksi A = 3.33 in2
B.
Find the maximum axial l
CIVE 335
1.3.A
Due Date
9-4-08
Assignment #
3
Problem 1.3 A - D
p.18
NAME (Last, First)
By constructing the parallelogram of forces, determine the resultants for the pairs of forces.
40 lb 90 70 lb 40 lb R ) 1.3.B 70 lb
Pythagorean Theorem: R2 = (40 lb)2
CIVE 335
1 AB a)
Due Date
9-4-08
Assignment #
3B
Problems 1.4 a - d
NAME (Last, First)
BC 141.4 lb (T) 200 lb
200 lb
141.4 lb
b) AB
BC 300 lb (T) 300 lb
300 lb
268.4 lb
c) BC 400 lb AB 400 lb 300 lb C d) BC 500 lb AC 500 lb 353.5 lb 353.3 lb 500 lb
CIVE 3
CIVE 335
1.3.A
Due Date
9-4-08
Assignment #
3
Problem 1.3 A - D
p.18
NAME (Last, First)
By constructing the parallelogram of forces, determine the resultants for the pairs of forces.
40 lb 90 70 lb 40 lb R ) 1.3.B 70 lb
Pythagorean Theorem: R2 = (40 lb)2
CIVE 335 Part Area (in2) 1 2 3 4 5
71.25
Due Date y (in)
0.00
9/2/08 b
7.50
Assignment # 2 d
9.50
Problems A.3 - a - A.3 - d A x y2 (in4)
0.00
p. 607
Io (in4)
535.86
Ix (in4)
535.86
Problem A.3.A
Io = bd3/12
Ix = I0 + Ay2
535.86
Part Area (in2) 1 2 3 4 5