Reactance, Inductive and Capacitive
Learning Objectives
By the end of this section, you will be able to:- Sketch voltage and current versus time in simple inductive, capacitive, and resistive circuits.
- Calculate inductive and capacitive reactance.
- Calculate current and/or voltage in simple inductive, capacitive, and resistive circuits.
Inductors and Inductive Reactance

AC Voltage in an Inductor
When a sinusoidal voltage is applied to an inductor, the voltage leads the current by one-fourth of a cycle, or by a 90º phase angle.
,
where V is the rms voltage across the inductor and XL is defined to be
,
with f the frequency of the AC voltage source in hertz (An analysis of the circuit using Kirchhoff’s loop rule and calculus actually produces this expression). XL is called the inductive reactance, because the inductor reacts to impede the current. XL has units of ohms (1 H = 1 Ω ⋅ s, so that frequency times inductance has units of (cycles/s)(Ω ⋅ s)=Ω)), consistent with its role as an effective resistance. It makes sense that XL is proportional to L, since the greater the induction the greater its resistance to change. It is also reasonable that XL is proportional to frequency f, since greater frequency means greater change in current. That is, ΔI/Δt is large for large frequencies (large f, small Δt). The greater the change, the greater the opposition of an inductor.
Example 1. Calculating Inductive Reactance and then Current
(a) Calculate the inductive reactance of a 3.00 mH inductor when 60.0 Hz and 10.0 kHz AC voltages are applied. (b) What is the rms current at each frequency if the applied rms voltage is 120 V?
Strategy
The inductive reactance is found directly from the expression XL = 2πfL. Once XL has been found at each frequency, Ohm’s law as stated in the equation I = V/XL can be used to find the current at each frequency.Solution for (a)
Entering the frequency and inductance into the equation XL = 2πfL givesXL = 2πfL = 6.28(60.0/s)(3.00 mH) = 1.13 Ω at 60 Hz.
Similarly, at 10 kHz,XL = 2πfL = 6.28(1.00 × 104/s)(3.00 mH) = 188 Ω at 10 kHz.
Solution for (b)
The rms current is now found using the version of Ohm’s law in Equation I = V/XL, given the applied rms voltage is 120 V. For the first frequency, this yields.
Similarly, at 10 kHz,
.
Discussion
The inductor reacts very differently at the two different frequencies. At the higher frequency, its reactance is large and the current is small, consistent with how an inductor impedes rapid change. Thus high frequencies are impeded the most. Inductors can be used to filter out high frequencies; for example, a large inductor can be put in series with a sound reproduction system or in series with your home computer to reduce high-frequency sound output from your speakers or high-frequency power spikes into your computer.Capacitors and Capacitive Reactance

AC Voltage in a Capacitor
When a sinusoidal voltage is applied to a capacitor, the voltage follows the current by one-fourth of a cycle, or by a 90º phase angle.
,
where V is the rms voltage and XC is defined (As with XL, this expression for XC results from an analysis of the circuit using Kirchhoff’s rules and calculus) to be
,
where XC is called the capacitive reactance, because the capacitor reacts to impede the current. XC has units of ohms (verification left as an exercise for the reader). XC is inversely proportional to the capacitance C; the larger the capacitor, the greater the charge it can store and the greater the current that can flow. It is also inversely proportional to the frequency f; the greater the frequency, the less time there is to fully charge the capacitor, and so it impedes current less.
Example 2. Calculating Capacitive Reactance and then Current
(a) Calculate the capacitive reactance of a 5.00 mF capacitor when 60.0 Hz and 10.0 kHz AC voltages are applied. (b) What is the rms current if the applied rms voltage is 120 V?
Strategy
The capacitive reactance is found directly from the expression in. Once XC has been found at each frequency, Ohm’s law stated as I = V/XC can be used to find the current at each frequency.
Solution for (a)
Entering the frequency and capacitance into, gives
.
Similarly, at 10 kHz,
.
Solution for (b)
The rms current is now found using the version of Ohm’s law in I = V/XC, given the applied rms voltage is 120 V. For the first frequency, this yields.
Similarly, at 10 kHz,
.
Discussion
The capacitor reacts very differently at the two different frequencies, and in exactly the opposite way an inductor reacts. At the higher frequency, its reactance is small and the current is large. Capacitors favor change, whereas inductors oppose change. Capacitors impede low frequencies the most, since low frequency allows them time to become charged and stop the current. Capacitors can be used to filter out low frequencies. For example, a capacitor in series with a sound reproduction system rids it of the 60 Hz hum.Resistors in an AC Circuit

AC Voltage in a Resistor
When a sinusoidal voltage is applied to a resistor, the voltage is exactly in phase with the current—they have a 0º phase angle.
Section Summary
- For inductors in AC circuits, we find that when a sinusoidal voltage is applied to an inductor, the voltage leads the current by one-fourth of a cycle, or by a 90º phase angle.
- The opposition of an inductor to a change in current is expressed as a type of AC resistance.
- Ohm’s law for an inductor is
where V is the rms voltage across the inductor., - XL is defined to be the inductive reactance, given by
with f the frequency of the AC voltage source in hertz., - Inductive reactance XL has units of ohms and is greatest at high frequencies.
- For capacitors, we find that when a sinusoidal voltage is applied to a capacitor, the voltage follows the current by one-fourth of a cycle, or by a 90º phase angle.
- Since a capacitor can stop current when fully charged, it limits current and offers another form of AC resistance; Ohm’s law for a capacitor is
where V is the rms voltage across the capacitor., - XC is defined to be the capacitive reactance, given by
. - XC has units of ohms and is greatest at low frequencies.
Conceptual Questions
1. Presbycusis is a hearing loss due to age that progressively affects higher frequencies. A hearing aid amplifier is designed to amplify all frequencies equally. To adjust its output for presbycusis, would you put a capacitor in series or parallel with the hearing aid’s speaker? Explain.
2. Would you use a large inductance or a large capacitance in series with a system to filter out low frequencies, such as the 100 Hz hum in a sound system? Explain.
3. High-frequency noise in AC power can damage computers. Does the plug-in unit designed to prevent this damage use a large inductance or a large capacitance (in series with the computer) to filter out such high frequencies? Explain.
4. Does inductance depend on current, frequency, or both? What about inductive reactance?
5. Explain why the capacitor in Figure 4(a) acts as a low-frequency filter between the two circuits, whereas that in Figure 4(b) acts as a high-frequency filter.

6. If the capacitors in Figure 4 are replaced by inductors, which acts as a low-frequency filter and which as a high-frequency filter?
Problems & Exercises
1. At what frequency will a 30.0 mH inductor have a reactance of 100 Ω?
2. What value of inductance should be used if a 20.0 kΩ reactance is needed at a frequency of 500 Hz?
3. What capacitance should be used to produce a 2.00 MΩ reactance at 60.0 Hz?
4. At what frequency will an 80.0 mF capacitor have a reactance of 0.250 Ω?
5. (a) Find the current through a 0.500 H inductor connected to a 60.0 Hz, 480 V AC source. (b) What would the current be at 100 kHz?
6. (a) What current flows when a 60.0 Hz, 480 V AC source is connected to a 0.250 μF capacitor? (b) What would the current be at 25.0 kHz?
7. A 20.0 kHz, 16.0 V source connected to an inductor produces a 2.00 A current. What is the inductance?
8. A 20.0 Hz, 16.0 V source produces a 2.00 mA current when connected to a capacitor. What is the capacitance?
9. (a) An inductor designed to filter high-frequency noise from power supplied to a personal computer is placed in series with the computer. What minimum inductance should it have to produce a 2.00 kΩ reactance for 15.0 kHz noise? (b) What is its reactance at 60.0 Hz?
10. The capacitor in Figure 4(a) is designed to filter low-frequency signals, impeding their transmission between circuits. (a) What capacitance is needed to produce a 100 kΩ reactance at a frequency of 120 Hz? (b) What would its reactance be at 1.00 MHz? (c) Discuss the implications of your answers to (a) and (b).
11. The capacitor in Figure 4(b) will filter high-frequency signals by shorting them to earth/ground. (a) What capacitance is needed to produce a reactance of
for a 5.00 kHz signal? (b) What would its reactance be at 3.00 Hz? (c) Discuss the implications of your answers to (a) and (b).
12. Unreasonable Results In a recording of voltages due to brain activity (an EEG), a 10.0 mV signal with a 0.500 Hz frequency is applied to a capacitor, producing a current of 100 mA. Resistance is negligible. (a) What is the capacitance? (b) What is unreasonable about this result? (c) Which assumption or premise is responsible?
13. Construct Your Own Problem Consider the use of an inductor in series with a computer operating on 60 Hz electricity. Construct a problem in which you calculate the relative reduction in voltage of incoming high frequency noise compared to 60 Hz voltage. Among the things to consider are the acceptable series reactance of the inductor for 60 Hz power and the likely frequencies of noise coming through the power lines.
Glossary
- inductive reactance:
- the opposition of an inductor to a change in current; calculated by XL = 2πfL
- capacitive reactance:
- the opposition of a capacitor to a change in current; calculated by
Selected Solutions to Problems & Exercises
1. 531 Hz3. 1.33 nF
5. (a) 2.55 A (b) 1.53 mA
7. 63.7 µH 9. (a) 21.2 mH (b) 8.00 Ω
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