Book Edition | 1st Edition |
Author(s) | Larson |
ISBN | 9781285447100 |
Publisher | Cengage |
Subject | Math |
Put 2 green marbles and 1 blue marble in a bag. Perform each experiment 36 times. Record each result as GG (green, green), GB (green, blue), or BB (blue, blue) using tally marks. A result of GB or BG represents the same result.
Randomly draw two marbles from the bag.
If you have 2 green balls and 1 blue ball, the probability of getting a green ball is 2/3, and the probability of getting a blue ball is 1/3.
Since it was stated that a combination of BB is possible, then I suppose the first ball drawn will be put back inside the bag.
So the probability of getting a green ball the second time, having a combination of GG (green,green) is 2/3*2/3 = 4/9
The probability of getting a blue ball the second time, having a combination of BB (blue,blue) is 1/3*1/3 = 1/9
The probability of getting a blue ball the second time while having green as the first one, having a combination of GB (green,blue) is 2/3*1/3= 2/9
The probability of getting a green ball the second time while having blue as the first one, having a combination of BG (blue,green) is 1/3*2/3= 2/9
Since the results GB and BG was stated to be the same, then the probability of getting both combination is 2/9 + 2/9 = 4/9
Multiplying these probability values by 36, we get:
GG: 4/9 * 36 =16
BB: 1/9 * 36 =4
GB&BG:4/9 * 36 =16
Drawing these as tally marks (I also included BB in the table below):
GG | (IIIII) (IIIII) (IIIII) I |
GB | (IIIII) (IIIII) (IIIII) I |
BB | IIII |
The answer would be:
GG | (IIIII) (IIIII) (IIIII) I |
GB | (IIIII) (IIIII) (IIIII) I |
BB | IIII |