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Assume that an incorrectly adjusted lawn mower is operated in a garage such that the combustion reaction in the engine is: C8H18 + (17/2)O2 -> 8CO +...

Assume that an incorrectly adjusted lawn mower is operated in a garage such that the combustion reaction in the engine is:
C8H18 + (17/2)O2 -> 8CO + 9H2O
If the dimensions of the garage are 3.0 by 5.0 by 5.0 meters, how many grams of gasoline must be burned to raise the level of CO in the air to 1000 ppm by volume at STP?
Hint: Calculate volume of garage, mol carbon monoxide, get mass octane from chemical equation
I could do it with formaldehyde but I'm lost on the gasoline...I tried and tried, ughh

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