Each of three players is deciding between the pure strategies go and stop. The payoff to go is 120/m where m is
the number of players that choose go, and the payoff to stop is 55 (which is received regardless of what the other players do). Find all Nash equilibria in mixed strategies.
If each player chooses go. Let q denote go and 1-q denote stop
(1-q) ^2* 120 + 2* q* (1-q) * 60 + q^2* 40 = 55
How do we solve the equation to get to q=.71
We get the equation : 4 0 q 2 1 2 0 q + 6 5 = 0 This is a quadratic equation in q The possible roots of... View the full answer