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A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64

squares of a chess board. On the second square the King would place two grains of​ wheat, on the third​ square, four grains of​ wheat, and on the fourth square eight grains of wheat. If the amount of wheat is doubled in this way on each of the remaining​ squares, what is the total weight in tons of all the wheat that will be placed on the first 51


51 ​squares? (Assume that each grain of wheat weighs​ 1/7000 pound. Remember that 1 tonequals


=2000 ​lbs.)

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Now total grains on the first 51 squares =1(2^51 -1)/(2-1)= (2^51... View the full answer

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