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Let t > 0 and f(x) = e^(tx).

This question was answered on Jul 20, 2016. View the Answer

Let t > 0 and f(x) = e^(tx). We call Pn the Lagrange polynomial, of at most degree n-1, which agree with f at the points 1,2,··· ,n

  1. Check that; for any positive integer n and any x ∈ R, f(n)(x) = (t^n)(e^(tx))

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Hello, Step 1: For n = 1: f'(x) = t*e^(tx) = (t^1)(e^(tx)) = 8/12 * 7/11 * 6/10 * 5/9 Step 2: Assume that for any random... View the full answer

This question was asked on Jul 20, 2016 and answered on Jul 20, 2016.

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