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This question was created from MA Lab 5 Kepler Laws.docx https://www.coursehero.com/file/33630782/MA-Lab-5-Kepler-Lawsdocx/

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Could you help answers B-E. I have found A to be 5.

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5. Use the ellipse tool from Lesson 2 (shown in Figure 5-2) to prove that the semimajor axis of an ellipse
is a planet's average orbital radius:
A. Orbital radius when the planet is closest to the
Sun: perihelion =
AU
planet
B. Orbital radius when the planet is farthest from the
Sun: aphelion =
AU
C. Average of perihelion and aphelion =
orbital radius
AU
D. Length of the major axis of the ellipse =
Sun
other
(at one focus)
focus
AU
E. Length of the semimajor axis of the ellipse =
AU
planet's
orbital path
Are the average orbital radius (C) and the semimajor
[ellipse)
axis (E) equal?
Figure 5-2 Shown here is the ellipse tool from Lesson 2.

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A) 5 AU B) 15 AU... View the full answer

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