When the helix axis of a closed circular double stranded DNA of 2340 bp is constrained to lie flat on a plane, the DNA has a twist (T) of 212. When released, the DNA writhes and takes up its normal twist of 10.4 bp per turn (B conformation).
determine Lo for this circular DNA
Indicate the values of the linking number (L), writhing number (W) and twist (T) for both the constrained and unconstrained conformations of the DNA circle
What is the superhelical density , sigma, of both the unconstrained and constrained DNA circles?
for circular constrained DNA W =0 so linking no (L) is equal to Twist (T) = 212.... View the full answer