A spherical cell with diameter of 60 micrometers ('a', the radius, = 30 micrometers) has a surface area of 1.1 x10^-4 cm^2.
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# A spherical cell with diameter of 60 micrometers ("a", the radius, = 30 micrometers) has a surface

area of 1.1 x10^-4 cm^2. If it has a resting potential of -60 mV and it has an action potential that reaches +40 mV at its peak and -70 mV at its undershoot. What is the number of excess unit negative charges on the membrane at rest? By what percent must this change for the membrane potential to reach the undershoot (-70 mV)? To perform your calculations assume that the membrane has a capacitance of 1 microFarad/cm^2, and use that fact that there are 6.2 x 10^+18 unit negative charges/Coulomb of negative charge.

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