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Problem 7-5 Students arrive at the Administrative Services Office at an average of one every 24 minutes, and their requests take on average 12

This problem deals with calculating the average wait times in a line and probability. Any help is appreciated :)

Problem 7-5 Students arrive at the Administrative Services Office at an average of one every 24 minutes, and their requests take on average 12 minutes to be processed. The service counter is staffed by only one clerk, Judy Gumshoes, who works eight hours per day. Assume Poisson arrivals and exponential service times. a. What percentage of time is Judy idle? (Round your answer to 2 decimal places.) Percentage of time % b. How much time, on average, does a student spend waiting in line? (Round your answer to the nearest whole number.) Average time minutes c. How long is the (waiting) line on average? (Round your answer to 2 decimal places.) Average waiting line students d. What is the probability that an arriving student (just before entering the Administrative Services Office) will find at least one other student waiting in line? (Round your answer to 4 decimal places.) Probability 50
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Dear Student, Please find attached... View the full answer

9624026.doc

= 12 customers/hour or 2 customers/hour (12/60) = 24 customers/hour or 4 customers/hour (24/60)
Solution-a
1-/ = 1-2/4 = 0.50 or 50%
Solution-b
Wq = / (-)
Wq = 2/4(4-2)
Wq = 2/8 or 15 Minutes...

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