mam help Saved to 1m (- The IVT eauhette applied he ﬁnd azeru. Use the [VT (Intermediate Value Theorem) to show that ﬁx) = exhas a zero. ms) is tnntinunui ee [0,1], rm) s n , rm = e, se we eah use the IVT m shew there is a seee in [0.1]

f[):] is suhhhuuus ee [71.2], m] < 0 . [(2) e a, se we eah use the m he shew these is e eere in [71,2] f[):] is eehhhueus ee [72.1], £02] < u , [(1) e a, se we eah use the m he shew these is a eere, between [72,1] ‘1')‘3‘5 1he IVT cmnolhe applied he ﬁnd azeru. 1. Use the IVT [Intermediate Value Theorem) to Show that ﬁx) = hlxihas a zeros (‘ Yeu can eet use the [VT te shew there is asese m [2.4]

r Yeueahusetheivne shnwthereisazereiu [a 5.2] (- [4, 2.99999] (e [3 mm“, a] (- Yeu can eet use the WT te shew that these is a me in [.5, 2] (‘ “Winn“ (- TheIVTeauhetheappiiedheﬁhdaxesuaeywhese, (‘ Everywhere 1. Use the IVT [Intermediate Value Theorem) to Show that “X1 = 5 inEX) + 1has a zero. Yeu can use the IVT te shew these is a zero in [71.1] 1. Use the IVT [Intermediate Value Theorem) to Show that “X1 = X2 - 3has a zero in

the interval [-4.4]. Yeu can use the IVT te shew these 15 a zero ie [71.21 You can use the IVT to shew that there is :\ zeru in [71, l]

(- ms) is suhhhuuus ee [74.4]. mg: 11m): 13, se we m. net use the IVTla shew there is a zero. 33'5”) The IVT eauhet'ee applied he ﬁnd azeru anywhere

(- f[):] is eehhhueus eu [4.41.371]: 72, (4) : 11, se we eah use the WT he shew theee is a zero, hetweeu [71,4]. (‘ fps) is eehhhueus on [-4.4]. «.13: .2, ecu) : -3, se we m. use the nrr ee shew there is a aeee, hetweeu [4,0] EHCl Hf :lo Hmr‘m I 7—|—+ 3‘2: 5 Am

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