I'm stuck on this question,
find B(t) = 3 +0.6sin(2*pi*/4.9)t.
Here is my calculations
B'(t)= 0.6cod(2pi/4.9)t * (2pi/4.9)
=pi/4.9cos(2pi/4.9)t
Can you point out my error?
thanks James
Top Answer
B'(t) = 0 . 6 s i... View the full answer
I'm stuck on this question,
find B(t) = 3 +0.6sin(2*pi*/4.9)t.
Here is my calculations
B'(t)= 0.6cod(2pi/4.9)t * (2pi/4.9)
=pi/4.9cos(2pi/4.9)t
Can you point out my error?
thanks James
B'(t) = 0 . 6 s i... View the full answer
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