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# Consider the Archimedian Spiral r = 56 + 3, 6 E [0, 21:] plotted below in black. The tangent to the spiral when 6 = Jr is plotted in blue. A

how can i solve with this question?

Consider the Archimedian Spiral r = 56 + 3, 6 E [0, 21:] plotted below in black. The tangent to the spiral when 6 = Jr is plotted in blue. A parametric form of this spiral can be found by using t = 6 as the parameter:
11(1) = [(3 + 51) c050), (3 + 51?) sin(t)] . Find the point 610:) = l ' E.
The Cartesian equation of the tangent to the curve at (101') is y = l E! E-
The Cartesian equation of the normal to the curve at 0(11') is y=l fan- Note: the Maple syntax for [:r, 0] is [PL 0] and you may ﬁnd concepts from the previous Week 9 topic useful here.

a(pi) = (-(3+5pi) , 0) equation of tangent... View the full answer

• please give me full explanation
• GeneralAntelope1036
• May 07, 2018 at 6:13am
• beside, this answer is not correct..
• GeneralAntelope1036
• May 07, 2018 at 6:13am

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