suppose that the acceleration of an object is given by a(t)=5t^(2/3)+2e^(-t). the velocity of the object at time 0 is v(0)=8 and its positio at time 0 is s(0)=-3. find s(t)

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a(t)=5t 2/3 +2e -t v(t)= 5(3/5)t 5/3 - 2e -t +C => v(t) = 3t 5/3 - 2e -t +C Since... View the full answer

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The function for the position of the object is s ( t )... View the full answer