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# limx-> cos((((x+1)(3-x^2))/(x^3-)) how do I solve trigonometric limits such as this one?

limx->∞ cos((((πx+1)(3-x^2))/(x^3-π))

how do I solve trigonometric limits such as this one?

﻿ lim ​ x → ∞ ​ ​ c o s ( ​ ( x ​... View the full answer

• I don't understand the step where you multiply the top and bottom by x^3. Are you factoring it?
• Aug 09, 2018 at 4:54pm
• No, for the numerator I have taken out the one x from the (pi x + 1) and x^2 form the (3 - x^2). Similarly for denominator I have take out x^3 from the (x^3 - pi), You can check this by multiplying the terms.
• abhisheksingla
• Aug 09, 2018 at 5:00pm

Great question... View the full answer

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