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I need help with this calculus problem. I'd appreciate any help

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Applying to the first integral:  ​ d t ​ ​ d ​ ​ ∫ ​ 0 ​ t ​ ​ ​ 5 x + 1 ​ ​ x ​ 2 ​ ​ + 1... View the full answer

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 ​ d t ​ ​ d ​ ​ ∫ ​ 0 ​ t ​ ​ ​ 5 x + 1 ​ ​ x ​ 2 ​ ​ + 1 ​ ​ d t = ​ 5 t + 1 ​... View the full answer

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