View the step-by-step solution to:

Let / : R - R be a continuously differentiable function. If x* is a solution to max,zo / (x). then f (at) = 0.

1) Those are two related practice questions please give me an answer for them so I can get a good idea of what I have to do with similar questions.





1. Let / : R - R be a continuously differentiable function. If x* is a solution to
max,zo / (x). then f (at) = 0.


Question ]
For each of the following . explain It the statement is true or false . It false , then provide a
counter- example. If true , then briefly Explain.


Q1 -1 : FOC
Consider a ditterentlable one—variable function fix) defined on [0,1], and let 3’ be a global maXImiser. 1, Suppose some claims “The first-order condition Is 3" (2’) = 0, " What is wrong with this statement? 2. Can you write down the set of global maximiser argmax formally? 3, Suppose that h be a weakly increastng function from R a R If some one claims that argmax fix} = argmmch(f(a:)) how do you respond? It this statement is incorrect, provide a correct
statement, 39,, no—relationship in general; one include the other; intersection is non—empty, yet no set—inclusion In general etc,

Top Answer

The way to approach this... View the full answer


The condition for * * to be
Global manimiser that $ ' ( x* ) = 0
is wrong .
This is only true when * * 6 ( 0 , 1)
But Global menima can also be
achieved at end points . It that
not be...

Sign up to view the full answer

Why Join Course Hero?

Course Hero has all the homework and study help you need to succeed! We’ve got course-specific notes, study guides, and practice tests along with expert tutors.


Educational Resources
  • -

    Study Documents

    Find the best study resources around, tagged to your specific courses. Share your own to gain free Course Hero access.

    Browse Documents
  • -

    Question & Answers

    Get one-on-one homework help from our expert tutors—available online 24/7. Ask your own questions or browse existing Q&A threads. Satisfaction guaranteed!

    Ask a Question
Ask a homework question - tutors are online