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I have no idea where to

even begin with this problem

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Visit this desmos link and interact with the graph in order to determine a d
so that if x - a < 6, then f(x) - L < . Please make sure your
response is accurate to within three decimal places.
Let f(x) = x^(2/3), and let x -+ 1, and suppose that & =.01.
Determine 8 so that if |x - a| < 8 , then If(x) - L| < E.

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