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Screen Shot 2019-06-25 at 7.17.23 PM.png

Don't I just get the

dy/dx of the equation and set that to zero?

Screen Shot 2019-06-25 at 7.17.23 PM.png

6. Determine the point(s) on the graph 9:2 + my + y2 = 4 at which the tangent line is horizontal.

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IMG_20190626_065714.jpg

( ) x + xyty' - 4
find dy a
dn
Diff we get, 2at Ray + 4 + 2 ydy = [ Note dlay )
2uth + ( 2 +2y) dy = 0. _
None tangent's hougontal
2) dy zo
Put in eqr @ dy 20
we get
2 nty = 0
2 ) y z - 2n -
Put 4...

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