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integral10.png

integral11.png

x+1
* = Inx+ In(x) |+c
Steps
x+1
ch
Apply u - substitution: u = In(x)
=
+ 1
Apply u - substitution: v = (" + u
=
Use the common integral: 1 adv = In(lv])
V
= In v
Substitute back v = e" +...

integral12.png

ck = x- 2me?+1 +c
1+ve
Steps
1
1+
Apply u - substitution: 1 = e*
Apply u - substitution: v = vu
=
Take the constant out: fa A(x)cax = a. [Ax)ax
=2.
cdv
Take the partial fraction of
1
v(v+ 1 )
=2...

integral13.png

X
1 - XV X
& =
V1-x
Steps
X
1-xVx
Apply u - substitution: u = v X
Take the constant out: Ja A(x)ckx =a. [Ax)xx
=
Apply u - substitution: v = 1 - 13
=2. ] - adv
Take the constant out: fa-...

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