This question has been answered
Question

Screen Shot 2019-10-01 at 1.44.32 PM.png

When I'm setting up the equations for P1/Pn, I first have 1. P1=1/(P2....Pn) and next 2. P1=1-P2-...Pn. Partially differentiating both with respect to Pn gives me -1/(P2....Pn-1)*1/(Pn)^2 for the first equation and 1 for the second equation. I'm confused on how I can get one single answer for ∂P1/∂Pn. I'm also confused about what it means when it says "Consider these 2 relations to implicitly determine the first 2 numbers as functions of the others, p1 = p1(p3,p4,...,pn), p2 = p2(p3,p4,...,pn).".

Image transcriptions

2. Consider n numbers p1, p2, . ..,Pn which both multiply and add to give 1: PIP2 . . . Pn = 1, Pi + p2 + . . . + Pn = 1. Consider these 2 relations to implicitly determine the first 2 numbers as functions of the others, p1 = p1 (P3, PA, . . ., Pn), P2 = P2 (P3, PA, . . .,Pn). Compute 921 (in terms of PI , P2, . . . , Pn).

Answered by Expert Tutors
Step-by-step explanation
The student who asked this found it Helpful
Overall rating 100%
Subject: Calculus, Math
Consider n numbers p1, p2, .,Pn which both multiply and add to give 1: PIP2 . Pn = 1, Pi + p2 + . + Pn = 1. Consider these 2 relations to implicitly...
Get unstuck

318,921 students got unstuck by Course
Hero in the last week

step by step solutions

Our Expert Tutors provide step by step solutions to help you excel in your courses