View the step-by-step solution to:

Question

Screen Shot 2019-10-01 at 1.44.32 PM.png

When I'm setting up

the equations for P1/Pn, I first have 1. P1=1/(P2....Pn) and next 2. P1=1-P2-...Pn. Partially differentiating both with respect to Pn gives me -1/(P2....Pn-1)*1/(Pn)^2 for the first equation and 1 for the second equation. I'm confused on how I can get one single answer for ∂P1/∂Pn. I'm also confused about what it means when it says "Consider these 2 relations to implicitly determine the first 2 numbers as functions of the others, p1 = p1(p3,p4,...,pn), p2 = p2(p3,p4,...,pn).".

Screen Shot 2019-10-01 at 1.44.32 PM.png

2. Consider n numbers p1, p2, . ..,Pn which both multiply and add to give 1:
PIP2 . . . Pn = 1,
Pi + p2 + . . . + Pn = 1.
Consider these 2 relations to implicitly determine the first 2 numbers as functions of
the others, p1 = p1 (P3, PA, . . ., Pn), P2 = P2 (P3, PA, . . .,Pn). Compute 921 (in terms of
PI , P2, . . . , Pn).

Top Answer

Sign up to view the full answer

Why Join Course Hero?

Course Hero has all the homework and study help you need to succeed! We’ve got course-specific notes, study guides, and practice tests along with expert tutors.

-

Educational Resources
  • -

    Study Documents

    Find the best study resources around, tagged to your specific courses. Share your own to gain free Course Hero access.

    Browse Documents
  • -

    Question & Answers

    Get one-on-one homework help from our expert tutors—available online 24/7. Ask your own questions or browse existing Q&A threads. Satisfaction guaranteed!

    Ask a Question