View the step-by-step solution to:


Screen Shot 2019-10-13 at 11.50.42 PM.pngSo I know the answer is -27,

but I'm not sure why. I know it has to have a third real zero since one complex number would imply it's conjugate as a fourth zero, which is impossible. I also know that the product of the roots = c, so c = 6 times the third root. But how do I know if the third root is positive or negative? Since all the answer choices are negative, I know the third root is negative, but I don't know why. And even then, I'm not sure how to go about finding what values of c are "possible". I don't see why it couldn't theoretically have a root in between it's two known ones. Any help is appreciated! I guess I don't know much about the behavior of cubic functions, or how the derivative is relevant here.

Screen Shot 2019-10-13 at 11.50.42 PM.png

65. Let p(x) be the polynomial x3 + ax2 + bx + c, where a, b, and c are real constants. If
p(—-3) = p(2) = 0 and p'(—3) < 0, which of the following is a possible value of c '2‘ (A) -27
(B) —18
(C) -6
(D) -3 1 (E) —5

Top Answer

Here is a detailed explanation... View the full answer

Sign up to view the full answer

Other Answers

After working on your question, I... View the full answer


Why Join Course Hero?

Course Hero has all the homework and study help you need to succeed! We’ve got course-specific notes, study guides, and practice tests along with expert tutors.

  • -

    Study Documents

    Find the best study resources around, tagged to your specific courses. Share your own to gain free Course Hero access.

    Browse Documents
  • -

    Question & Answers

    Get one-on-one homework help from our expert tutors—available online 24/7. Ask your own questions or browse existing Q&A threads. Satisfaction guaranteed!

    Ask a Question